What is the empirical formula of a substance that is 53.5% C, 15.5% H, 31.1% N?

1 answer:

7 0

For each carbon, hydrogen and nitrogen. You have to divide each percentage by its atomic mass.
C = 53.5/12.0107 = 4.45436
H = 15.5/1.00794 = 15.377899
N= 31.1/14.0067 = 2.220365

Round the number to significant figures
C = 4.45
H =15.4
N =2.22

Divide Each Number by the smallest number out of the three
so N = 2.22/2.22 =1
H = 15.4/2.22= 6.9 =7
C = 4.45/2.22= 2
So the Formula Should Be <span>C2H7N</span>

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