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Kruka [31]
3 years ago
14

2 Write a word equation and

Chemistry
1 answer:
joja [24]3 years ago
6 0

Answer:

Zinc oxide is react with sulphuric acid to give zinc sulphate and water.

zinc oxide +sulphuric acid ⇒ zinc sulphate + water

Zno    +H2So4 ⇒ZnSo4 + H2O

SULPHURIC ACID = H2SO4

ZINC SULPHATE =ZnO

Explanation:

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State and explain the observations when chlorine gas is bubbled through a solution of
natta225 [31]

Answer:

A reduction-oxidation (redox) reaction will occur.

Chlorine gas (Cl2) will accept electrons to form Cl- ions.

The Iron(II) ions (Fe2+) will lose electrons to form Fe3+ ions. (Iron (III) ions)

Fe2+ ions are green, while Fe3+ ions are yellow,

so the observation will be the solution turning from green to yellow.

5 0
3 years ago
What is the mass of OH- in Ca(OH)2
Ne4ueva [31]
Oxygen: 16.00 g/mol
Hydrogen: 1.01 g/mol

The mass would be 17.01 g/mol
5 0
3 years ago
A solution of LiCl in water has XLiCl = 0.0800. What is the molality? A solution of LiCl in water has XLiCl = 0.0800. What is th
Kay [80]

Answer:

mol LiCl = 4.83 m

Explanation:

GIven:

Solution of LiCl in water XLiCl = 0.0800

Mol of water in kg = 55.55 mole

Find:

Molality

Computation:

mole fraction = mol LiCl / (mol water + mol LiCl)

0.0800 = mol LiCl / (55.55 mol + mol LiCl)

0.0800 mol LiCl + 4.444 mol = mol LiCl

mol LiCl - 0.0800 mol LiCl = 4.444 mol

0.92 mol LiCl = 4.444 mol

mol LiCl = 4.83 m

7 0
3 years ago
How many grams are 3.01 × 1023 molecules of CuSO4?
zvonat [6]
Answer is: 79.8 grams of copper(II) sulfate.
N(CuSO₄) = 3.01·10²³; number of molecules.
n(CuSO₄) = N(CuSO₄) ÷ Na.
n(CuSO₄) = 3.01·10²³ ÷ 6.02·10²³ 1/mol.
n(CuSO₄) = 0.5 mol; amount of substance.
m(CuSO₄) = n(CuSO₄) · M(CuSO₄).
m(CuSO₄) = 0.5 mol · 159.6 g/mol.
m(CuSO₄) = 79.8 g; mass of substance.
M - molar mass.
4 0
3 years ago
60 POINTS! PLEASE ANSWER!
Mumz [18]
I would have helped but I didn’t understand it sorry that I didn’t answer :(
6 0
2 years ago
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