Question

When a 10 mL graduated cylinder is filled to the 10 mL mark, the mass of the water was measured to be 9.925 g. If the density of water is taken to be 0.9975 g/mL, what is the percent error for the 10 mL of water,

Answer 1

Measured volume = 10 ml 
mass = 9.925 g 
density = 0.9975 g/ml
density = $\frac{mass}{volume}$ 
so actual volume = $\frac{mass}{density}$ = $\frac{9.925}{0.9975}$ = 9.95 mL
Percentage Error = $\frac{measured volume - Actual volume}{actual volume}$ x 100 
= $\frac{10 - 9.95}{9.95}$ x 100 = 0.5 % error