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3 years ago

If a 30 gram sample of Copper shots (specific heat = 0.385 J/gºC) changed from 27ºC to 90ºC, how much heat was involved?

Chemistry

2 answers:

Readme [11.4K]3 years ago

4 0

Answer:

A = 728J

Explanation:

Mass of substance = 30g

Specific capacity of copper = 0.385J/g°C

Initial temperature (T1) = 27°C

Final Temperature (T2) = 90°C

Heat energy (Q) = ?

Heat Energy (Q) = Mc∇T

Q = heat energy

M = mass of the substance

C = specific heat capacity of the substance

∇T = change in temperature of the substance = T2 - T1

Q = mc∇T

Q = mc×(T2 - T1)

Q = 30 × 0.385 × (90 - 27)

Q = 11.55 × 63

Q = 727.65J

The heat energy required to raise 30g of copper sample from 27°C to 90° is 728J

Natasha_Volkova [10]3 years ago

3 0

Answer:

728J

Explanation:

The following data were obtained from the question:

Mass (M) = 30g.

specific heat capacity (C) = 0.385 J/gºC.

Initial temperature (T1) = 27ºC

Final temperature (T2) = 90ºC

Change in temperature (ΔT) = T2 – T1 = 90°C – 27 = 63°C

Heat (Q) =...?

The heat involved can be obtained as illustrated below:

Q = MCΔT

Q = 30 x 0.385 x 63

Q = 728J

Therefore the heat involved is 728J

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<h3>Stoichiometry</h3>

The term stoichiometry refers to mass - volume relationships. Stoichiometry can be used to calculate the amount, mass or volume of reactants and products from the balanced reaction equation.

The equation of the reaction is written as follows;

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Answer:

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