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Zarrin [17]
4 years ago
6

Jared says he can always multiply two numbers together to find their least common multiple (LCM). Jared uses these pairs of numb

ers to show his method of finding the LCM. please help me
Mathematics
1 answer:
lorasvet [3.4K]4 years ago
3 0

not necessary true, let the numbers 4 and 6

4•6=24 but lcm(4,6)=12

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Marcus has 127 baseball cards in his collection. Gabriel has 56 cards in his collection. Gabriel divides his collection evenly a
vovangra [49]
56/7 = 8
Marcus = 127 + 8 = 135
8 0
3 years ago
Which expressions are equivalent to 5+ (-3)(6x – 5)?
Viefleur [7K]

Hello

5 + ( -3) ( 6x - 5 )

= 5 - 3*6x + 5*3

= -18x + 20

Good day. ;)

4 0
3 years ago
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Figure MNPQR will be reflected across the x-axis to create figure M'N'P'Q'R'. Which rule describes this transformation? A.(x,y)
kolbaska11 [484]

Answer:

D.(x,y) → (x,-y)

Step-by-step explanation:

If it is reflected across the X-axis, then the X variable will stay the same and the Y variable will change.

I hope this helps!! Good luck!!

(Sorry if I'm wrong! It's kinda awkward because it is placed in the second quadrant instead of the first.)

8 0
3 years ago
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Someone help please
Mrac [35]
Use ax^2 + bx + c = 0

ac = -8
b = 2

The factors are 4 and -2.
Plug them into the equation:

x^2 + 4x - 2x - 8

Then factorise it:

x ( x + 4) - 2 (x + 4)

so m = 4

(x + 4)^2

4 0
3 years ago
Question (in need of help)
mr Goodwill [35]
<h3><u>Required</u><u> Answer</u><u>:</u><u>-</u></h3>

This is an right angle ∆ and the side lengths containing a right angle are 9 and 11.

By Pythagoras theoram,

{p}^{2}  +  {b}^{2}  =  {h}^{2}

where p is the perpendicular, b is the base and h is the hypotenuse.

Plugging the values,

{9}^{2}  +  {11}^{2}  =  {h}^{2}

Then,

h =  \sqrt{ {9}^{2}  +  {11}^{2} }

h = 14.12(approx.)

<h3><u>Hence:</u><u>-</u></h3>

The x of the right angled ∆ = <u>1</u><u>4</u><u>.</u><u>1</u><u>2</u>

6 0
3 years ago
Read 2 more answers
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