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frosja888 [35]
3 years ago
7

Someone help please

Mathematics
1 answer:
Mrac [35]3 years ago
4 0
Use ax^2 + bx + c = 0

ac = -8
b = 2

The factors are 4 and -2.
Plug them into the equation:

x^2 + 4x - 2x - 8

Then factorise it:

x ( x + 4) - 2 (x + 4)

so m = 4

(x + 4)^2

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aev [14]
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Mult. all terms by 2 to remove the fractions:

2y - 4 > x - 2

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4 0
4 years ago
I can't figure it out ​
Strike441 [17]

Answer:

\Huge\boxed {v=17360³}

Step-by-step explanation:

● formulas of valume = πr²h

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Hope it's helps you

4 0
3 years ago
Read 2 more answers
If f(x) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B9%7D" id="TexFormula1" title="\frac{1}{9}" alt="\frac{1}{9}" align=
boyakko [2]

Answer:

Solution given:

f(x) = \frac{1}{9} x-2

let f(x)=y

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interchanging role of x and y

x= \frac{1}{9} y-2

x+2= \frac{1}{9} y

y=9(x+2)

y=9x+18

So

<u>F</u><u>-</u><u>¹</u><u>(</u><u>x</u><u>)</u><u>=</u><u>9</u><u>x</u><u>+</u><u>1</u><u>8</u>

<u>a</u><u>n</u><u>d</u>

<u>F</u><u>-</u><u>¹</u><u>(</u><u>-</u><u>1</u><u>)</u><u>=</u><u>9</u><u>*</u><u>-</u><u>1</u><u>+</u><u>1</u><u>8</u><u>=</u><u>-</u><u>9</u><u>+</u><u>1</u><u>8</u><u>=</u><u>9</u>

6 0
3 years ago
Quadrilateral ABCD has coordinates A (3,1) B (4,4) C (7,5) D (6,2). Quadrilateral ABCD is a ?
ASHA 777 [7]
The Quadrilateral ABCD with coordinates (3, 1), (4, 4), (7, 5), (6, 2) is a rhombus because its length and width are both square root of 10 units and adjacent sides are not perpendicular. This can be seen by plotting the points you can either plot it or by using programs.

I hope this helps, God bless, and have a great day!
Brainliest is always appreciated :)
3 0
3 years ago
Read 2 more answers
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Mariana [72]

The answer is 4.

The easiest way to determine the value of statements like this is to turn the percentage into a decimal and then multiply.

20% * 20

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4

6 0
4 years ago
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