Answer:
{- 3, - 2, 0, 2 }
Step-by-step explanation:
The range is the y- coordinates of the points
(- 4, - 3 ) , (- 1, - 2 ) , (- 2, 0 ) , (0, 2 )
The y- coordinates are - 3, - 2, 0, 2
Then the range is { - 3, - 2, 0, 2 }
Answer:
Please use " ^ " for exponentiation: x^2 + 2x + 8 ≤ 0.
Let's solve this by completing the square:
x^2 + 2x + 8 ≤ 0 => x^2 + 2x + 1^2 - 1^2 + 8 ≤ 0. Continuing this rewrite:
(x + 1)^2 + 7 ≤ 0
Taking the sqrt of both sides: (x + 1)^2 = i*sqrt(7)
Then the solutions are x = -1 + i√7 and x = -1 - i√7
There's something really wrong here. I've graphed your function, x^2 + 2x + 8, and can see from the graph that there are no real roots, but only complex roots. Please double-check to ensure that you've copied down this problem correctly.
Answer:
w≥15
Step-by-step explanation:
Subtract 80 from both sides to get -2w≤-30. Divide both sides by -2. Because it is negative, flip it. You will get w≥15.
Answer:
wat is it
Step-by-step explanation:
