The statement that -6 is in the domain of f(g(x)) is true
<h3>Complete question</h3>
If f(x) = -2x + 8 and g(x) = 
, which statement is true?
- -6 is in the domain of f(g(x))
- -6 is not in the domain of f(g(x))
<h3>How to determine the true statement?</h3>
We have:
f(x) = -2x + 8
Start by calculating the function f(g(x)) using:
f(g(x)) = -2g(x) + 8
Substitute
Set the radicand to at least 0
Subtract 9 from both sides
This means that the domain of f(g(x)) are real numbers greater than or equal to -9. i.e. -9, -8, -7, -6, ...........
Hence, the statement that -6 is in the domain of f(g(x)) is true
Read more about domain at:
brainly.com/question/24539784
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Answer:
y=4x+2 or f(x)=4x+2
Step-by-step explanation:
This is because the equation format for a line is y=mx+b, the slope is m and the y-intercept is b. So all you have to do is fill it out to get y=4x+2. Or the other way I listed the equation is right too. Hope this helps!
Answer:
y=−1/7
for the picture is y=-57/7
Step-by-step explanation:
<h3>1. 8= -7y +7</h3>
Switch:sides
-7y+7=8
subtract 7 from both sides
-7y=1
divide both sides by -7
y=−1/7
<h3>2.so for 8/y+7=-7</h3>
multiply both sides by (y+7)
8/y+7(y+7)=-7(y+7)
simplify 8=-7(y+7)
flip
-7(y+7)=8
divide both sides by -7
y+7=-8/7
subtract 7 from both sides
and simplify
y=-57/7
7x+3y=-1
x+y=-3
8x+4y=-4
2x+y=-1
y=-1-2x
x+y=-3
x-1-2x=-3
-x=-2
x=2
y=-1-2*2=-1-4=-5
Area of circle = πr²
Area of circle = π x 12 x 12
Area of circle = 452.4cm² (nearest tenth)
