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Ira Lisetskai [31]
3 years ago
15

What is theory of relativity and why this theory made??????

Physics
2 answers:
Ymorist [56]3 years ago
7 0

Answer:

e=mc2 made to relate mass with energy . bcoz energy can neither b created nor b destroyed

frosja888 [35]3 years ago
6 0

Answer:

Leave it bro!!!.....

I have got members!!!

But if you want then come up from my id #LV89QRGCL

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Which of these items would be a renewable resource?
Irina18 [472]
Trees can be a renewable source , we use them to breath , we make paper out of them , we make houses and etc.

i hope this helps
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James and Juan were at the highest point in the football stadium, dropping water balloons on people below. Many of the balloons
Fofino [41]
When you add more water to the balloon, it makes it heavier. Therefore it would weigh the balloon down ( increasing mass) and increasing the energy to plummet down. So the answer is B.
4 0
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How much energy from the sun actually reaches the corn answer?
Serhud [2]
The energy from the sun that reaches the corn is about two billionths.
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es la atmósfera que se percibe en un cuento de acuerdo a la manera de pensar y sentir de los personajes no se ve sólo se siente​
masya89 [10]

Answer:

can you please ask in english

8 0
3 years ago
A rock is projected upward from the surface of the moon, at time t = 0.0 s, w a velocity of 30 m/s. The acceleration due to grav
Vinvika [58]
<h2>Answer: 277.777 m</h2>

Explanation:

The situation described here is parabolic movement. However, as we are told that the rock was<u> projected upward from the surface</u>, we will only use the equations related to the Y axis.

In this sense, the movement equations in the Y axis are:

y-y_{o}=V_{o}.t+\frac{1}{2}g.t^{2}    (1)

V=V_{o}-g.t    (2)

Where:

y  is the rock's final position

y_{o}=0  is the rock's initial position

V_{o}=30\frac{m}{s} is the rock's initial velocity

V is the final velocity

t is the time the parabolic movement lasts

g=1.62\frac{m}{s^{2}}  is the acceleration due to gravity at the surface of the moon

As we know y_{o}=0 , equation (2) is rewritten as:

y=V_{o}.t+\frac{1}{2}g.t^{2}    (3)

On the other hand, the maximum height  is accomplished when V=0:

V=V_{o}-g.t=0    (4)

V_{o}-g.t=0    

V_{o}=g.t    (5)

Finding t:

t=\frac{V_{o}}{g}    (6)

Substituting (6) in (3):

y=V_{o}(\frac{V_{o}}{g})+\frac{1}{2}g(\frac{V_{o}}{g})^{2}    (7)

y_{max}=\frac{{V_{o}}^{2}}{2g}    (8)  Now we can calculate the maximum height of the rock

y_{max}=\frac{{(30m/s)}^{2}}{(2)(1.62m/s^{2})}   (9)

Finally:

y_{max}=277.777m  

4 0
3 years ago
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