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3 years ago

What formula relates mass volume and density?

Physics

1 answer:

katovenus [111]3 years ago

8 0

The formula that relates the 3 variables, namely: mass, volume, and density is: Density = mass / volume.

Let us identify each variable:

Density - more accurately called the volumetric mass density of a substance is its mass per unit volume. It is a key concept that examines how materials communicate in a lot of things, i.e weather, material sciences, engineering, and other fields of science.

Mass – defined as a property of a physical body in Physics, and when a net force is applied, it results to the measure of a specific object’s resistance to acceleration.

Volume - <span>contained or occupied by the space of a substance or shape (either by a solid, liquid, gas or plasma state)</span>

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This mathematical model describes the changes that occur in a sample of water as its temperature increases. Based on this model,

Sergio039 [100]

Answer:A. I expect the molecules in ice to move more quickly than the molecules in water vapor.

Explanation:

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3 years ago

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What would happen to the wavelength of a wave as the velocity is increased and the

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Answer: wavelength will increase

Explanation:

Velocity is directly proportional to wavelength,as the velocity is increased, wavelength is also increased

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4 years ago

What distance will a vehicle travel before coming to a complete stop from a speed of 70 mph, (a) When the vehicle is traveling o

OLga [1]

Answer:

(a), The SSD will be 723.9 ft.

(b-1), The SSD will be 620.2 ft.

(b-2), The SSD will be $723.91>SSD>620.2$

(c), The SSD will be 910.5 ft.

Explanation:

Given that,

Speed = 70 mph

Suppose, a perception reaction time of 2.5 sec and the coefficient of friction is 0.35

We need to calculate the stopping sight distance

Using formula of SSD

$SSD=1.47\times v\times t+\dfrac{v^2}{30\times(f\pm g)}$

Where, v = speed of vehicle

t = perception reaction time

f = coefficient of friction

g = gradient of road

(a). If the gradient of road is zero.

Then, the stopping sight distance will be

$SSD=1.47\times 70\times 2.5+\dfrac{70^2}{30\times(0.35)}$

$SSD=723.9\ ft$

(b-1). If the gradient of road is 0.1

Then, the stopping sight distance will be

$SSD=1.47\times 70\times 2.5+\dfrac{70^2}{30\times(0.35+0.1)}$

$SSD=620.2\ ft$

(b-2). If the grade continuously decrease then the SSD will be increase.

But if the grade is increase then the SSD will be decrease and for flat grade the SSD will be more.

So, The SSD will be $723.91>SSD>620.2$

(c). When the vehicle is traveling downhill on a roadway of constant grade then the vehicle take will be more SSD

So, The SSD will be

$SSD=1.47\times 70\times 2.5+\dfrac{70^2}{30\times(0.35-0.1)}$

$SSD=910.5\ ft$

Hence, (a), The SSD will be 723.9 ft.

(b-1), The SSD will be 620.2 ft.

(b-2), The SSD will be $723.91>SSD>620.2$

(c), The SSD will be 910.5 ft.

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4 years ago

When thermal insulation, such as spun glass or rock wool, is placed beneath the roof of a house, then in cold weather the insula

siniylev [52]

Answer:

c. slow the flow of heat from inside the house to the outside.

Explanation:

Thermal insulation not completely stops the flow of heat but slow down the process of flowing of heat from inside the house to the outside.

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3 years ago

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A circuit contains an EMF source, a resistor R, a capacitor C, and an open switch in series. The capacitor initially carries zer

Flura [38]

Answer:

t = 1.098*RC

Explanation:

In order to calculate the time that the capacitor takes to reach 2/3 of its maximum charge, you use the following formula for the charge of the capacitor:

$Q=Q_{max}[1-e^{-\frac{t}{RC}}]$ (1)

Qmax: maximum charge capacity of the capacitor

t: time

R: resistor of the circuit

C: capacitance of the circuit

When the capacitor has 2/3 of its maximum charge, you have that

Q=(2/3)Qmax

You replace the previous expression for Q in the equation (1), and use properties of logarithms to solve for t:

$Q=\frac{2}{3}Q_{max}=Q_{max}[1-e^{-\frac{t}{RC}}]\\\\\frac{2}{3}=1-e^{-\frac{t}{RC}}\\\\e^{-\frac{t}{RC}}=\frac{1}{3}\\\\-\frac{t}{RC}=ln(\frac{1}{3})\\\\t=-RCln(\frac{1}{3})=1.098RC$

The charge in the capacitor reaches 2/3 of its maximum charge in a time equal to 1.098RC

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4 years ago