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Nostrana [21]
3 years ago
11

What formula relates mass volume and density?

Physics
1 answer:
katovenus [111]3 years ago
8 0

The formula that relates the 3 variables, namely: mass, volume, and density is: Density = mass / volume.

 

Let us identify each variable:

Density - more accurately called the volumetric mass density of a substance is its mass per unit volume. It is a key concept that examines how materials communicate in a lot of things, i.e weather, material sciences, engineering, and other fields of science.

Mass – defined as a property of a physical body in Physics, and when a net force is applied, it results  to the measure of a specific object’s resistance to acceleration.

 

Volume - <span>contained or occupied by the space of a substance or shape (either by a solid, liquid, gas or plasma state)</span>

You might be interested in
26. Keenan found the mass of a book to be 4.56*10^ -2 kg . What is the mass of the book in milligrams?​
vagabundo [1.1K]

Taking into account the rule of three for the change of units, the mass of the book is 45600 miligrams.

First of all, the rule of three is a mathematical tool that helps you quickly solve proportionality problems.

Having three known values ​​and one unknown, a proportional relationship is established between all of them in order to find the fourth term of the proportion.

If the relationship between the magnitudes is direct (when one magnitude increases, so does the other; or when one magnitude decreases, so does the other), the rule of three is applied as follows, where a, b and c are known values ​​and x is the unknown to calculate:

a → b

c → x

So: x=\frac{cxb}{a}

Being 1 kg equivalent to 1000000 milligrams, In this case the rule of three is applied as follows: if 1 kg equals 1000000 milligrams, 4.56×10⁻² kg equals how many milligrams?

1 kg → 1000000 milligrams

4.56×10⁻² kg  → x

So:

x=\frac{4.56x10^{-2} kg x1000000 miligrams }{1 kg}

<u><em>x=45600 miligrams</em></u>

In summary, the mass of the book is 45600 miligrams.

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7 0
3 years ago
What do you like about science?​
Inessa [10]

Answer:

nngh have

bjruh hjrhhj be rnrnnrnrnnnrnjrjnnnnnnnnrnrn n n and I was nrn

Explanation:

jbbbbbhhhjjnnnnnnnnnnjhvcc

Explanation:

5 0
3 years ago
Rama's weight is 40kg. She is carrying a load of 20 kg up to a height of 20 m . What work does she do?​
Sliva [168]

Answer:

\huge\star{\underline{\mathtt{\blue{Answer}}}}\huge\star...

<h2>PE=<em>work done</em></h2><h2><em>m</em><em>gh</em><em>=</em><em>2</em><em>0</em><em>×</em><em>1</em><em>0</em><em>×</em><em>2</em><em>0</em><em>.</em><em>.</em></h2>

\huge\boxed{\fcolorbox{white}{blue}{mgh=4000}}

.

<em>I </em><em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

7 0
3 years ago
If two different theories describe experimental observations equally well, can one be said to be more valid than the other (assu
Andreas93 [3]

Answer:

No

Explanation:

In such situations we cannot determine which one is more valid as both serves the purpose well.

Two theories are carried out in different environment and circumstance keeping different parameters and one can opt for any number of ways to carry out that experiment but what matter at the end is the accuracy they bring.

Each of the theory is a new discovery and follows all the possible logical rules hence it is not possible to decide which one is more valid.

3 0
3 years ago
A satellite is in a circular orbit 21000 km above the Earth’s surface; i.e., it moves on a circular path under the influence of
mina [271]

Answer:

(orbital speed of the satellite) V₀ = 3.818 km

Time (t) = 4.5 × 10⁴s

Explanation:

Given that:

The radius of the Earth is 6.37 × 10⁶ m;    &

the acceleration of gravity at the satellite’s altitude is 0.532655 m/s

We can calculate the orbital speed of the satellite by using the formula:

Orbital Speed (V₀) = √(r × g)

radius of the orbit (r) = 21000 km + 6.37 × 10⁶ m

                                  = (2.1 × 10⁷ + 6.37 × 10⁶) m

                                  = 27370000

                                  = 2.737 × 10⁷m

Orbital Speed (V₀) = √(r × g)

Orbital Speed (V₀) = √(2.737 × 10⁷  × 0.532655 )

                              = 3818.215

                              = 3.818 × 10³

                             = 3.818 Km

To find the time it takes to complete one orbit around the Earth; we use the formula:

Time (t) = 2 π × \frac{r}{V_o}

            = 2 × 3.14 × \frac{2.737*10^7}{3.818*10^3}

            = 45019.28

            = 4.5 × 10 ⁴ s

6 0
3 years ago
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