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Mariana [72]
3 years ago
9

The average speed between earth and the sun is 1.50 x10^8 km. Calculate the average speed of the Earth in its orbit in kilometer

s per second.
Physics
2 answers:
cluponka [151]3 years ago
7 0

Answer:

The average speed of the earth in its orbit is 29.86km/s

Explanation:

The average distance between the Earth and the Sun is 1.50x10^{8} km.

The average speed of the earth in its orbit can be found by the next equation :

v = \frac{2 \pi r}{T}  (1)

Where r is the radius and T is the period.

In this case, the orbit of the Earth can be considered as a circle

(r = 1.50x10^{8}km) instead of an ellipse.

It takes 1 year to the Earth to make one revolution around the Sun. Therefore, its period will be 365.25 days.

Notice that to express the period in terms of seconds, the following is needed:

365.25d . \frac{86400s}{1d} ⇒ 31557600s

Then, equation 1 can be used:

v = \frac{2 \pi (1.50x10^{8}km)}{31557600s}

v = 29.86km/s

Anestetic [448]3 years ago
4 0

Complete Question

The average distance  between earth and the sun is 1.50 x10^8 km. Calculate the average speed of the Earth in its orbit in kilometres per second.

Answer:

The value is   v  = 29.89 \ km/s

Explanation:

From the question we are told that

  The  average distance  is   r  =  1.50 *10^{8} \  km

The  average speed is mathematically represented as

       v  =  \frac{2 \pi r}{t}

Here t is the time taken to circle round the  sun which is equal to 1 year

Now converting this to seconds we have

     t =  1 *  365 * 24 * 60 * 60  =  3.154*10^{7} \  s

So

       v  =  \frac{2 *3.142 *1.50 *10^{8}  }{3.154*10^{7}}

       v  = 29.89 \ km/s

   

   

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Explanation:

Period=1/frequency

Period=1/295 seconds

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3 years ago
A disk of radius 10 cm is pulled along a frictionless surface with a force of 16 N by a string wrapped around the edge. At the i
drek231 [11]

Answer:

t = 0.2845Nm (rounded to 4 decimal places)

Explanation:

The disk rotates at a distance of an arc length of 28cm

Arc length = radius × central angle × π/180

28cm = 10cm × central angle × π/180

Central angle = \frac{28}{10} × 180/π ≈ 160.4°

Torque (t) = rFsin(central angle) , where F is the applied force

Radius in meters = 10/100 = 0.1m

t = 0.1m × 16N × sin160.4°

t = 0.2845Nm (rounded to 4 decimal places)

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3 years ago
Who speaks the line "Lord, what fools these mortals be"?
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The answer is D.Puck.

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3 years ago
A major-league pitcher can throw a ball in excess of 40.1 m/s. If a ball is thrown horizontally at this speed, how much will it
mote1985 [20]

Answer:

The ball will drop 0.881 m by the time it reaches the catcher.

Explanation:

The position of the ball at time "t" is described by the position vector "r":

r = (x0 + v0x · t, y0 + v0y · t + 1/2 · g · t²)

Where:

x0 = initial horizontal position.

v0x = initial horizontal velocity.

t = time.

y0 = initial vertical position.

v0y = initial vertical velocity.

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).

When the ball reaches the catcher, the position vector will be "r final" (see attached figure).

The x-component of the vector "r final", "rx final", will be 17.0 m. We have to find the y-component.

Using the equation of the x-component of the position vector, we can calculate the time it takes the ball to reach the catcher (notice that the frame of reference is located at the throwing point so that x0 and y0 = 0):

x = x0 + v0x · t

17.0 m = 0 m + 40.1 m/s · t

t = 17.0 m/ 40. 1 m/s = 0.424 s

With this time, we can calculate the y-component of the vector "r final", the drop of the ball:

y = y0 + v0y · t + 1/2 · g · t²

Initially, there is no vertical velocity, then, v0y = 0.

y = 1/2 · g · t²

y = -1/2 · 9.8 m/s² · (0.424 s)²

y = -0.881 m

The ball will drop 0.881 m by the time it reaches the catcher.

8 0
3 years ago
Before Collision Consider a system to be one train car moving toward another train car at rest When the train cars collide, the
erma4kov [3.2K]

Answer:

2,400kg * m/s

Explanation:

You are missing some information in the question but the rest could be found some where else.

The question gives the masses and starting velocity of each car.

Car 1: m = 600kg and sv = 4m/s

Car 2: m 400kg and sv = 0m/s

Find the momentum of both cars.

Car 1: 600 * 4 = 2400

Car 2: 400 * 0 = 0

Add both.

2400 + 0 = 2400

Best of Luck!

7 0
3 years ago
Read 2 more answers
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