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Mariana [72]
3 years ago
9

The average speed between earth and the sun is 1.50 x10^8 km. Calculate the average speed of the Earth in its orbit in kilometer

s per second.
Physics
2 answers:
cluponka [151]3 years ago
7 0

Answer:

The average speed of the earth in its orbit is 29.86km/s

Explanation:

The average distance between the Earth and the Sun is 1.50x10^{8} km.

The average speed of the earth in its orbit can be found by the next equation :

v = \frac{2 \pi r}{T}  (1)

Where r is the radius and T is the period.

In this case, the orbit of the Earth can be considered as a circle

(r = 1.50x10^{8}km) instead of an ellipse.

It takes 1 year to the Earth to make one revolution around the Sun. Therefore, its period will be 365.25 days.

Notice that to express the period in terms of seconds, the following is needed:

365.25d . \frac{86400s}{1d} ⇒ 31557600s

Then, equation 1 can be used:

v = \frac{2 \pi (1.50x10^{8}km)}{31557600s}

v = 29.86km/s

Anestetic [448]3 years ago
4 0

Complete Question

The average distance  between earth and the sun is 1.50 x10^8 km. Calculate the average speed of the Earth in its orbit in kilometres per second.

Answer:

The value is   v  = 29.89 \ km/s

Explanation:

From the question we are told that

  The  average distance  is   r  =  1.50 *10^{8} \  km

The  average speed is mathematically represented as

       v  =  \frac{2 \pi r}{t}

Here t is the time taken to circle round the  sun which is equal to 1 year

Now converting this to seconds we have

     t =  1 *  365 * 24 * 60 * 60  =  3.154*10^{7} \  s

So

       v  =  \frac{2 *3.142 *1.50 *10^{8}  }{3.154*10^{7}}

       v  = 29.89 \ km/s

   

   

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Answer:

a) F=1.044\times 10^9\ N

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d) Treat the humans as though they were points or uniform-density spheres.

Explanation:

Given:

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a)

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F=G.\frac{M.m}{r^2}

where:

G=6.67 \times 10^{-11}\ m^3.kg^{-1}.s^{-2} = gravitational constant

F=6.67\times10^{-11}\times \frac{6.4\times 10^{23}\times 80}{(3.4\times 10^{6})^2}

F=1.044\times 10^9\ N

b)

The magnitude of the gravitational force exerted by the human on Mars is equal to the force by the Mars on human.

F'=F

F'=1.044\times 10^9\ N

c)

When a similar person of the same mass is standing at a distance of 4 meters:

F_p=6.67\times10^{-11}\times \frac{80\times 80}{4}

F_p=1.0672\times10^{-7}\ N

d)

The gravitational constant is a universal value and it remains constant in the Universe and does not depends on the size of the mass.

  • Yes, we have to treat Mars as spherically symmetric so that its center of mass is at its geometric center.
  • Yes, we also have to ignore the effect of sun, but as asked in the question we have to calculate the gravitational force only due to one body on another specific body which does not brings sun into picture of the consideration.
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Explanation:

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A person driving her car at 48 km/h approaches an intersection just as the traffic light turns yellow. She knows that the yellow
trasher [3.6K]

Answer:

She must stop the car  before interception, distance traveled 12.66 m

Explanation:

We will take all units to the SI system

Vo = 48Km / h (1000m / 1Km) (1h / 3600s) = 13.33 m / s

V2 = 70 Km / h = 19.44 m / s

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X = Vo t + ½ to t²

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X = 13.33 2 + 1.2 (-7) 2²

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Let's analyze what happens if you accelerate, let's calculate the acceleration of the vehicle

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This is the acceleration to try to pass the interception, now let's calculate the distance it travels in the time the traffic light changes from yellow to red (t = 2.0 s)

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X = 13.33 2 + ½ 0.926 2²

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In order to climb, you need to work against work done by gravity on the pack.
Hence work done by you = work done by gravity on pack 
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Power is the rate of work done.
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