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Rainbow [258]
2 years ago
14

Determine whether the statement is true or false. If f '(c) = 0, then f has a local maximum or minimum at c.

Physics
1 answer:
ankoles [38]2 years ago
4 0

It is False that, If f '(c) = 0, then f has a local maximum or minimum at c.

Local maximum and minimum points are very distinctive on the graph of a function and are thus, helpful in grasping the shape of the graph. Either a local minimum or a local maximum can be considered a local extremum.

A counterexample can be used for:

f(x) = x³

f'(x) = 2 × x²

and,

f'(0) = 2×0² = 0

However, the assertion is false because x = 0 is actually an inflection point rather than a maximum or minimum in f(x) = x³.

Know more about f(x) here: brainly.com/question/28058540

#SPJ4

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______ uses radioactive materials to create contrast in the body and help form images of the structure and function of organs.
satela [25.4K]

Answer:

Nuclear medicine or PET scanning (Positron Emission Tomography)

Explanation:

Not super sure what your question is looking for but I think it can be either. PET is a technology used in the nuclear medicine field, and nuclear medicine is a broad field of using the technology the question described.

8 0
2 years ago
Name some applications of white surfaces.
timofeeve [1]
White marble is a white surface
7 0
3 years ago
Read 2 more answers
The velocity of the water in the pipe at right is given by V1 = 0.5t m/s and V2 = 1.0t m/s, where t is in seconds. Determine the
Nonamiya [84]

Answer:

A) At point 1, local acceleration = 0.5 m/s²

At point 2, local acceleration = 1.0 m/s²

B) Average Eulerian convective acceleration over the two points in the cross section shown = 0.5 m/s²

This value is positive indicating an increase in velocity and acceleration kf the fluid as the cross sectional Area of flow reduces.

Explanation:

Local acceleration at those points is the instantaneous acceleration at those points and it is given as

a = dv/dt

At point 1, v₁ = 0.5 t

a₁ =dv₁/dt = 0.5 m/s²

At point 2, v₂ = 1.0 t

a₂ = dv₂/dt = 1.0 m/s²

b) Average Eulerian convective acceleration over the two points in the cross section shown = (change of velocity between the two points)/time

Change of velocity between the two points = v₂ - v₁ = 1.0t - 0.5t = 0.5 t

Time = t

Average acceleration = 0.5t/t = 0.5 m/s²

This value is positive indicating an increase in velocity and acceleration kf the fluid as the cross sectional Area of flow reduces.

8 0
3 years ago
A toy cannon uses a spring to project a 5.24-g soft rubber ball. The spring is originally compressed by 5.01 cm and has a force
salantis [7]

Answer:

Speed will be equal to 1.40 m/sec

Explanation:

Mass of the rubber ball m = 5.24 kg = 0.00524 kg

Spring is compressed by 5.01 cm

So x = 5.01 cm = 0.0501 m

Spring constant k = 8.08 N/m

Frictional force f = 0.031 N

Distance moved by ball d = 15.8 cm = 0.158 m

Energy gained by spring

KE=\frac{1}{2}kx^2=\frac{1}{2}\times 8.08\times 0.0501^2=0.0101J

Energy lost due to friction

W=Fd=0.031\times 0.158=0.0048J

So remained energy to move the ball = 0.0101 - 0.0048 = 0.0052 J

This energy will be kinetic energy

\frac{1}{2}mv^2=0.0052

\frac{1}{2}\times 0.00524\times v^2=0.0052

v = 1.40 m/sec

7 0
3 years ago
Which options correctly describe the velocity of the object represented in the graph?
kirza4 [7]
There is no graph ...
7 0
2 years ago
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