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Anon25 [30]
3 years ago
14

How do you subtract two negative numbers?

Mathematics
1 answer:
ZanzabumX [31]3 years ago
8 0

when you have 2 negative numbers you actually add the 2nd number to the first one

 example:

-4 - -2 =  becomes -4 + 2 = -2

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OlgaM077 [116]
7:50 AM /PM is the time
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Answer this in two minutes
gregori [183]

Hey there! :)

Answer:

y = x - 3.

Step-by-step explanation:

Given:

Slope = 1

Point on line: (8, 5)

Plug these into the formula y = mx + b, where:

m = slope

x = x coordinate of point

y = y coordinate of point

5 = 1(8) + b

5 = 8 + b

Subtract both sides by 8:

5 - 8 = 8 -8 + b

-3 = b

Rewrite the equation:

y = x - 3.

4 0
3 years ago
Find the common fraction equivalent to 0.12
jonny [76]
The answer is:  " \frac{4}{33} "  .
______________________________
Given:  0.1212121212..... repeating ;  write that value as a fraction;
______________________________________________________
In other words; we are given:  "0.1212121212..... repeating infinitely" ;  

→ that is to say; "0.12 ...  ;  {the "12" decimal portion repeats infinitely} ; 
_______________________________________________________
→ We write this value, as a fraction, as:  "12/99" ;
__________________________________________
→Explanation:
__________________________________________ 


Note:  "0.99999999...... repeating infinitely;  =  "1" .
_________________________________________
→Since:

Let us say that we have: 

"x = 0.999999 ; repeating infinitely;  

In order words, let us say we have: "x = 0.9.... ;  the "9" decimal repeats infinitely; 
_____________________________________________________
   Then "10x" ;  (that is: "10" multlipled by "x";  or "10*x" or "10x" );  is equal to:

"10" * (0.999999.....)  = 9.99999999...... (the "9" decimal repeats infinitely);

in other words:  10x = 9.99999999....

Divide each side by "10" ;

to get "x = 0.9999999....." ; the decimal "9" repeats indefinitely...." ;

But if you have:  "10x = 10" ;  divide each side of the equation by "10" ; 
   you get: "x = 1" . 
____________________
Also,  if "x = 0.9999...(repeating infinitely); 

then:  10x = 9.99999.
_______________________________________________
           10x  =  9.999999999999999......
       −     x  =  0.999999999999999.......
    _____________________________________
            9x  =  9.00000000000000000000.....

 →  9x = 9 ; 

Divide each side of the equation; to get; 

 9x /9 = 9/ 9 ;  to get:  x = 1 ; and we have: x = 0.9999.... ;  so
  x= 0.99999.... = 1 ; 
__________________________________________________
So, if the numbers "12" is repeating, we divie "12" by "99" ; 
  that is; we divide "12" by "two 9's" ;  since "12" is a "TWO-digit number"; a "two-digit number" is being repeated infinitely.
________________________________________
            So;  0.12121212.....(the "12" is the decimal that repeats infinitely);            
                   
=  12/99 ;  which can be simplified;

Divide each side (both the numerator AND the denominator); by "3" ;
_________________________________________
  " 12/99 "  =  "(12÷3) / (99÷3) = 4/33 " .
_________________________________________
The answer is:  \frac{4}{33}  .
_________________________________________
8 0
3 years ago
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Which answer is equivalent to 4 1/3*4 1/6?<br> a. 16<br> b .6√​16<br> c. 2<br> d. 3√​4
Talja [164]

Answer:

<h2>c. 2</h2>

Step-by-step explanation:

4^\frac{1}{3}\cdot4^\frac{1}{6}\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=4^{\frac{1}{3}+\frac{1}{6}}=4^{\frac{1\cdot2}{3\cdot2}+\frac{1}{6}}=4^{\frac{2}{6}+\frac{1}{6}}=4^\frac{2+1}{6}=4^\frac{3}{6}=4^\frac{3:3}{6:3}=4^{\frac{1}{2}}\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\=\sqrt[2]{4^1}=\sqrt4=2

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3 years ago
Solve each equation. <br> 2y=7(y−2)+4<br> y = <br> 4x=6−2(2−x) <br> x =
aliya0001 [1]

Answer:

y=2 and x=1

Step-by-step explanation:

2y=7y-14+4

2y-7y=-14+4

-5y=-10/-5

y=2

4x=6-4+2x

4x-2x=6-4

2x=2/2

x=1

5 0
2 years ago
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