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4 years ago

The supercontinent in the continental drift hypothesis was called

Physics

1 answer:

Oksanka [162]4 years ago

8 0

Answer:

Pangaea

Explanation:

The Earth's crust is not one solid block but is made of different segments called tectonic plates. At one point it started to break apart. The land mass was present around the Paleozoic and Mesozoic eras. This land mass was called Pangaea

As a result all the water on Earth was a part of an ocean called Panthalassa. The concept of the one land mass and one water mass was proposed be Alfred Wagner.

Hence, the statement here is referring to Pangaea.

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When we look up in the sky the Sun appears about as big as the moon; however, we know that the Sun is much further away. Given t

Nady [450]

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3 years ago

Under very dim levels of illumination foveas react to increase the sensitivity of the optic nerve. rods are more light-sensitive

Alex777 [14]

Answer:

rods are more light sensitive than cones.

Explanation:

There are two types of photo receptors in retina of our eyes. 1 Rods and 2 Cones. Rods are about 120 million and they are more sensitive then the cones. But the rods are not sensitive to color. Cones help us in seeing the color and there are about 6 to 7 million cones that provide color sensitivity to our eyes. That is why in the dark or where their are dim levels of illumination rods provide us scotopic vision. Because rods are more light sensitive then the cones.

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4 years ago

Read 2 more answers

Learning Goal:

Rudiy27

Answer:

The questions are not complete so this is the complete questions

1. How much work W does the motor do on the platform during this process?

2. What is the angular velocity ωf of the platform at the end of this process?

3. What is the rotational kinetic energy, Ek, of the platform at the end of the process described above?

4. How long does it take for the motor to do the work done on the platform calculated in Part 1?

5. What is the average power delivered by the motor in the situation above?

6. . Note that the instantaneous power P delivered by the motor is directly proportional to ω, so P increases as the platform spins faster and faster. How does the instantaneous power P•f being delivered by the motor at the time t•f compare to the average power

P(average) calculated in Part e?

Explanation:

Given that,

The torque τ=25Nm

Moment of inertia I =50kgm²

The platform is initially at rest,

ω•i=0 rad/sec

Revolution the torque produce is 12

Then, θ=12 revolution

1 revolution=2πrad

So, θ=24πrad

1. Work done in a rotational motion is give as

W=τ•Δθ

Given that the τ=25Nm and the initial angular displacement is 0rad

The final angular displacement is 24πrad

Δθ =(θ2-θ1)

Δθ=24π-0

Δθ=24πrad

Then,

W=τ•Δθ

W=25(24π)

W=25×24π

W=1884.96J

To 4s.f, W=1885J

2. Final angular velocity ωf

Using the angular equation

ω•f²=ω•i²+2•α•Δθ

We need to get angular acceleration

The torque is given as

τ=I•α

Given that,

I is moment if inertia =50kgm²

τ=25Nm

α=τ/I

α= 25/50

α=0.5rad/s²

Now, using the angular acceleration

ω•f²=ω•i²+2•α•Δθ

ω•f²=0²+2×0.5×24π

ω•f²=0+75.398

ω•f²=75.398

ω•f=√75.398

ω•f=8.68 rad/sec.

3. We need to find rotational Kinetic energy and it is given as

K.E, = ½I•ω²

Given that, I=50kgm² and ω•f=8.68rad/sec

Then,

K.E, =½I•ω²

K.E, =½×50×8.68²

K.E, =1884.96J

To 4s.f,

K.E, =1885J

Which is the same as the work done by the motor.

4. Time taken to complete part 1,

Using the rotational equation

ω•f=ω•i+α•t

Since, ω•f=8.68 rad/sec and ω•i=0

And α=0.5rad/s²

Then,

ω•f=ω•i+α•t

8.68=0+0.5t

8.68=0.5t

Then, t=8.68/0.5

t=17.36secs

5. The average power of rotational motion is given as

P(average) =Workdone/timetaken

Since,

Work done =1884.96J

Time taken =17.36sec

P(average) =Workdone/timetaken

P(average)=1884.96/17.36

P(average)= 108.58Watts

To 4s.f

P(average)=108.6Watts

6. We need to find •, it is given as

• =τ•ωf

Given that, ω•f=8.68rad/sec, τ=25Nm

•=25×8.68

•=217Watts

Then, the ratio of • to P(average) is

Ratio = •/ P(average)

Ratio= 217/108.58

Ratio=1.9985

Then, the ratio is approximately 2

Ratio=2

5 0

4 years ago

Stars are classified mainly according to their distance from Earth.

Zielflug [23.3K]

The answer is b) false. Stars are mainly classified by their spectra (the elements they absorb) and their temperature.

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3 years ago