Answer:
w=255
Explanation:
The change in internal energy is given by the first law:
ΔE = Q - w
where ΔE is the change in internal energy of the system
q is the heat added to the system
w is the work done *by* the system on the surroundings
So, for the first phase of this process:
ΔE = Q - w
Q=160J
w=309J
ΔE = 160J - 309J = -149J
To bring the system back to its initial state after this, the internal energy must change by +149J (the system myst gain back the 149 J of energy it lost). We are told that the system loses 106 J of heat in returning to its initial state, so the work involved is given by:
ΔE = Q - w
+149J = -106J - w
255J = -w
w = -255J
I know that the relationship between altitude and atmospheric density is that the higher the altitude, the lesser the density, and the lower the altitude the higher the density. Lower density float to the top, and higher density is 'heavy' so it comes down
Answer: Have A Blessed Day!
Explanation:
Thanks for the information mate!
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Answer:
32 m and -2.4 m/s
Explanation:
Given:
v₀ = 25 m/s
t = 2.8 s
a = -9.8 m/s²
Find: Δy, v
Δy = v₀ t + ½ at²
Δy = (25 m/s) (2.8 s) + ½ (-9.8 m/s²) (2.8 s)²
Δy = 31.6 m
v = at + v₀
v = (-9.8 m/s²) (2.8 s) + 25 m/s
v = -2.44 m/s
Rounded to two significant figures, the bullet reaches a height of 32 m and a velocity of -2.4 m/s.
Answer:
166.67 N
Explanation:
Applying Pascal's principle,
Presure in the smaller piston(P') = Pressure in the bigger piston(P)
But,
Pressure = Force/Area
Pressure in the smaller piston(P') = Force applied to the smaller piston(F')/Area of the smaller piston(A')
Pressure in the bigger piston(P) = Force applied to the bigger piston(F)/Area of the bigger piston(A)
F'/A' = F/A.................. Equation 1
Make F the subject of the equation
F = F'A/A'.............. Equation 2
From the question,
Given: F' = 20 N, A = 120 cm², A' = 10 dm² = (10×100) = 1000 cm²
Substitute these values into equation 2
F = 20(1000)/120
F = 166.67 N
