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4 years ago

10

Please help me with this homework

2 answers:

VMariaS [17]4 years ago

8 0

Sunlight is used to heat up the liquid water so it evaporates, then it becomes the clouds and then it rains

hammer [34]4 years ago

7 0

It pokes a hole through the clouds.

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An astronaut in a spacecraft looks out her window and observes a comet travel in the opposite direction at a relative speed of 2

Sergeu [11.5K]

The velocity of the spacecraft with respect to the Sun is
$v_s = +114 m/s$
the velocity of the comet in the reference system of the spacecraft is
$v_c' = 237 m/s$

So, the velocity of the comet in the reference system of the Sun will be
$v_c = v_c'-v_s = -237 m/s - 114 m/s=-351 m/s$
And the negative sign tells us that the comet is directed toward the Sun.

7 0

3 years ago

Read 2 more answers

PLEASE HELP I WILL GOVE BRAINLIEST TO FIRST CORRECT ANSWER!!!!!

Dmitrij [34]

Answer is C is the correct answer

8 0

3 years ago

What is the precision (relative error) of the centripetal force divided by the mass if the velocity and the radius are each dete

Mrac [35]

The precision (relative error) of the centripetal force is 1%.

<h3>Relative error</h3>

This is the error in measurement of a variable obtained in comparison with other variables.

F = mv²/r

where;

F is centripetal force
m is mass
v is velocity
r is radius

F/m = v²/r

F/m = (0.01v)²/(0.01r)

F/m = 0.01v²/r

F/m = 1%(v²/r)

Thus, the precision (relative error) of the centripetal force is 1%.

Learn more about relative error here: brainly.com/question/13370015

5 0

3 years ago

What form of government concentrates power in a central government

spin [16.1K]

The answer is
Unitary system : All government power is held by a central government

8 0

3 years ago

Read 2 more answers

A cruise ship sails due south at 2.00 m/s while a coast guard patrol boat heads 19.0° north of east at 5.60 m/s. What are the x-

Lilit [14]

Answer:

The x-component and y-component of the velocity of the cruise ship relative to the patrol boat is -5.29 m/s and 0.18 m/s.

Explanation:

Given that,

Velocity of ship = 2.00 m/s due south

Velocity of boat = 5.60 m/s due north

Angle = 19.0°

We need to calculate the component

The velocity of the ship in term x and y coordinate

$v_{s_{x}}=0$

$v_{s_{y}}=2.0\ m/s$

The velocity of the boat in term x and y coordinate

For x component,

$v_{b_{x}}=v_{b}\cos\theta$

Put the value into the formula

$v_{b_{x}}=5.60\cos19$

$v_{b_{x}}=5.29\ m/s$

For y component,

$v_{b_{y}}=v_{b}\sin\theta$

Put the value into the formula

$v_{b_{y}}=5.60\sin19$

$v_{b_{y}}=1.82\ m/s$

We need to calculate the x-component and y-component of the velocity of the cruise ship relative to the patrol boat

For x component,

$v_{sb_{x}}=v_{s_{x}}-v_{b_{x}}$

Put the value into the formula

$v_{sb_{x}=0-5.29$

$v_{sb}_{x}=-5.29\ m/s$

For y component,

$v_{sb_{y}}=v_{s_{y}}-v_{b_{y}}$

Put the value into the formula

$v_{sb_{x}=2.-1.82$

$v_{sb}_{x}=0.18\ m/s$

Hence, The x-component and y-component of the velocity of the cruise ship relative to the patrol boat is -5.29 m/s and 0.18 m/s.

7 0

3 years ago