1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sleet_krkn [62]
3 years ago
10

Do machines create less work? Example: pulley system

Physics
1 answer:
kherson [118]3 years ago
6 0

Answer:

Technically, no the work of building machines is hard but in the long run, Yes they are easier after they're built.

Explanation:

You might be interested in
A current carrying wire of length 50cm is positioned perpendicular to a uniform magnetic field
RideAnS [48]

A current-carrying wire of length 50 cm is positioned perpendicular to a uniform magnetic field. The magnetic field strength is 0.6 Tesla.

<h3>What is magnetic field?</h3>

The magnetic field is the region of space where an object experiences a magnetic force as it enters the field.

Given is the wire of length 50 cm = 0.5 m and the current is 10.0 A. There is a resultant force of 3.0 N on the wire due to the interaction of the current and field.

The relation between magnetic field strength and current is

F = ILB

Substituting 50 for L, 10 for I and 3 for F, we get the magnetic field strength B.

3 = 10 × 0.5 × B

B= 0.6 Tesla

Therefore, the magnetic field strength is 0.6 Tesla.

Learn more about magnetic field.

#SPJ

3 0
1 year ago
Homework 7 Adaptive Follow-Up Problem 25.68 Item 4 Constants A cylindrical copper cable 3.30 km long is connected across a 220.0
xenn [34]

Answer:

 0.446 mm  

0.066 V/m

Explanation:

Given  

We are given the length of the copper cable L = 3.30 km and the potential difference is V = 220 V  

Solution  

(a) We want to find the diameter d of the cable when the dissipated power is P = 50W. The power consumed by the cable depends on its resistance R and it is given by equation in the form

P= V^2/R                                                (1)

Where V is the voltage in the cable. Now let us solve equation (1) for R and plug our values for V and P into equation (1) to get R  

R = V^2/P = (220)^2/(50) = 968Ω

Now we can determine the diameter of the copper wire. The resistance R of the wires depends on the area of the wire, resistivity and the length of the cable. Where equation gives us the relationship between these variables in the form  

R = pL/π*r^2                             (solve for r)

r = √pL/πR                             (2)

Now we can plug our values for Rep and L into equation (2) to get the radius of the cable where p for copper equals 1.72 x 10-8 Ω m

r =√pL/πR                    

 = √1.72 x 10-8 *3300m/968

 = 0.234 mm

Therefore, the diameter is d= 2r = 2(0.234  mm) =  0.446 mm  

(b) To determine the electric field we can use the values for the potential difference across the cable and the length of the cable, where the electric field is inversely proportional to the length of the cable as next  

E =V/L

  =220/3300m

  = 0.066 V/m

3 0
3 years ago
A light spring with a force coefficient 11.85 N/m is compressed by 14 cm as it is held between a 0.27 kg block on the left and a
lilavasa [31]

Answer:

A) Left = 6.14 m/s2 Right=2.765 m/s2   B) Left = 4.59 m/s2 Right= 1.215 m/s2

Explanation:

In the question we are given the spring constant which is 11.85 N/m and the compression of the spring is 14 cm. There are two blocks in front of the springs which are 0.27 kg and 0.6 kg respectively.

First, we need to calculate how much force the spring are going to exert on the masses when they are released. Since this force is not going to change for both cases, we only need to do it once.

The formula for calculation the force is F = k.x where k is the spring constant or force coefficient 11.85 N/m and the x is the compression which is 14 cm or 0.14 meters. If we put them in the equation we can find that F = 1.659 N

A) In the first case scenario, where the friction is equal to 0, we can use the formula F=m.a where F is the force applied by the release of the spring, m is the mass of the block and a is the acceleration.

For the first block, when we put 1.659 N and 0.27kg in the equation, a is calculated to be 6.14 m/s2.

For the second block, the same force of 1.659 N and 0.6 kg, a is calculated to be 2.765 m/s2.

B) In the second case scenario, where the friction is equal to 0.158, we first need to calculate its effect on each block. We need to use the formula      Fk = μ.N where μ is the friction constant and N is the normal force of the block which is m.g (where g = 9,81 m/s2).

The friction force for the first block is calculated to be 0.4184 N and the friction force for the second block is calculated to be 0.9299 N.

The total force for the first block is 1.659 N - 0.4184 N = 1.2405 N.

The total force for the second block is 1.659 N - 0.9299 N = 0.7290 N.

When we insert these numbers into the same equation we used to find the acceleration in the first case scenario, we can calculate the acceleration of the first block as 1.2405 = 0.27 x a  and a = 4.59 m/s2.

When we insert these numbers into the same equation we used to find the acceleration in the first case scenario, we can calculate the acceleration of the second block as 0.7290 = 0.6 x a  and a = 1.215 m/s2.

4 0
3 years ago
A baseball is thrown at an angle of 25 degrees, with a speed
Lana71 [14]

Answer:

vertical component = 9.7m/s

Explanation:

Vy= (23)sin25 = 9.7m/s

8 0
3 years ago
1. When red light shines on a red rose, what color do you see? Do the leaves become
Lubov Fominskaja [6]
This is hard sorry but I need to anwser
7 0
2 years ago
Read 2 more answers
Other questions:
  • PLEASE ANSWER QUICK!!! 2. Every magnet has _ unlike poles.
    7·1 answer
  • A cannon is mounted on a truck that moves forward at a speed of 5 m/s. The operator wants to launch a ball from a cannon so the
    12·1 answer
  • Can I get some help please?
    12·1 answer
  • Two identical tiny spheres of mass m =2g and charge q hang from a non-conducting strings, each of length L = 10cm. At equilibriu
    14·1 answer
  • You pick up a 3.4 kg can of paint from the ground and lift it to a height of 1.8 m. how much work do you do on the can of paint?
    5·1 answer
  • Two speakers face each other, and they each emit a sound of wavelength λ. One speaker is 180∘ out of phase with respect to the o
    12·1 answer
  • A guitar string of length L = 0.94 m is oriented along the x-direction and under a tension of T = 92 N. The string is made of st
    5·1 answer
  • Which of the following is not considered a behavior?
    11·2 answers
  • (a) Define moment of a force (1mk)
    14·1 answer
  • The speed of sound in air is 340 m/s. What is the wavelength of a soundwave that has a frequency of 502 Hz?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!