Answer:
The answer to your question is
a) t = 2.55 s
b) t = 5.5 s
Explanation:
Data
vo = 25 m/s
h = 2 m
g = 9.81 m/s
Formula
t = -(vo)/g
a)
t = -(25)/9.81
t = 2.55 s
b)
Tt = 2t
Tt = 2(2.55)
Tt = 5.1 s
Time in the last 10 m
10 = 25t + (1/2)(9.81)t²
Simplify
10 = 25t 4.91t²
4.9t² + 25t - 10 = 0
Solve the equation using an online calculator
t₁ = 0.37 s t₂ = -5.47 s
The correct answer is t₁, t₂ is incorrect because there are no negative answers.
Total time = 5.1 + 0.37
= 5.5 s
Answer:
Low-temperature blackbody
Explanation:
There are 3 types of blackbody temperatures.
Low-temperature blackbody
High temperature extended area blackbody
High-temperature cavity blackbody
A Low-temperature blackbody is a type of black body radiation that has the range of -40° C to 175° C, typically between 233 K and 448 K. A perfect fit for the temperature range mentioned in the question, "a few hundred Kelvin". Therefore, it's the kind of blackbody temperature that the object would emit.
Explanation:
d frequency I learned it last year
Answer:
Volume of balloon = 1000 cm^3
Explanation:
The head of a normal person can be assumed as a sphere with radius 10 cm.
Volume of sphere
, where r is the radius.
We have approximate radius = 10 cm.
Approximate volume of head 
In the given options the closest value to the approximate volume is 1000 cm^3.
So, volume of head = Volume of balloon = 1000 cm^3