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Igoryamba
3 years ago
5

What is this? Plz I need help...

Physics
1 answer:
RSB [31]3 years ago
4 0

Answer:

the time it takes for one complete back and forth swing

Explanation:

the Mark's is showing you the time it swings back and forth

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Which of these best shows how waves can affect matter? A) the moon’s gravity pulling the ocean a few feet up and down each day B
qaws [65]

Answer:

D: a buoy bobbing up and down in place with ocean waves

Explanation:

7 0
4 years ago
these four trucks are identical each box loaded on the truck has the same mass choose the truck that has the greatest force of g
likoan [24]

Answer:

the green truck

Explanation:

the truck has 6 boxes which weighs more than 4, 3, or 2

4 0
4 years ago
Read 2 more answers
Jim is driving a 2268-kg pickup truck at 19 m/s and releases his foot from the accelerator pedal. The car eventually stops due t
lord [1]

Answer:

The initial kinetic energy of the truck is 409374 J

Explanation:

This problem can be solved in two ways. Let´s solve it first in the easiest way.

The kinetic energy is calculated using this equation:

E = 1/2 · m · v²

Where:

E = kinetic energy

m = mass

v = velocity

Then, the kinetic energy of the truck will be:

E = 1/2 · 2268 kg · (19 m/s)² = 409374 J

And that´s it.

But we can complicate it a bit:

The kinetic energy is the work needed to move an object from rest to a desired velocity. If the object is moving, the work needed to stop it must be of the same magnitude as its kinetic energy (in the opposite direction to the movement).

The equation for work is:

W = F · d

Where:

W= work

F = force

d = distance

We know the magnitude of the force applied to the truck, but we do not know for how much distance that force was applied. The distance can be calculated using the equation for the position of an object moving in a straight line:

x = x0 + v0 · t + 1/2 · a · t²

where

x = position at time t

x0 = initial position

v0 = initial velocity

t = time

a = acceleration

But we still do not know the time nor the acceleration.

The acceleration can be obtained from the equation of force:

F = m · a

Where

F = force

m = mass

a = acceleration

Then:

900 N = 2268 kg ·a

a = 900 N /2268 kg = 0.397 m/s²

Now, we can calculate the time needed for the truck to stop. We know that at the final time, the velocity is 0. Then, we can use the equation for velocity to obtain that time:

v = v0 + a · t

Where:

v = velocity at time t

v0 = initial velocity

a = acceleration

t = time

Then:

v = 19 m/s - 0.397 m/s² · t

0 = 19 m/s - 0.397 m/s² · t

-19 m/s / -0.397 m/s² = t (acceleration is negative because it is opposite to the direction of the movement)

t = 47.86 s (The truck stoped at 47.86 s after releasing the foot from the accelerator pedal)

With the time and acceleration, we can calculate the traveled distance.

x = 0 m + 19 m/s · 47.86 s - 1/2 · 0.397 m/s² · (47.86s)²

x = 454.66 m (without rounding the acceleration nor the time, the value will be 454.86 m)

Now, we can calculate the work done to stop the truck which will be of the same magnitude as the kinetic energy:

W = 900 N · 454.66 m = 409194 J

(if you do all the calculations without rounding, you will get the same value as we calculated above using the equation of kinetic energy, 409374 J).

3 0
3 years ago
When radioactive tracers are used for medical scans, the tracers both decay in the body via radiation, as well as being excreted
irinina [24]

Answer:

Effective half-time of the tracer is 3.6 days

Explanation:

The formula for calculating the decay due to excretion for the first process is ;

\frac{dN_1}{dt } = - \lambda _e N_o

here ;

N_o = initial number of tracers

Then to the second process ; we have :

\frac{dN_2}{dt } = - \lambda _e N_o

The total decay is as a result of the overall process occurring ; we have :

\frac{dN_{total}}{dt } = \frac{dN_1}{dt} + \frac{dN_2}{dt}   ------ (1)

here ;

\frac{dN_{total}}{dt } = \lambda _{total} N_o

Putting the values in (1);we have :

- \lambda _{Total} N_o = - \lambda_e N_o + ( -\lambda r N_o})

\lambda _{Total} = \lambda_e + \lambda r

As we also know that:

\frac{1}{t_{1/2}} = \frac{[t_{1/2}]_{radiation}+[t_{1/2}]_{excretion}}{[t_{1/2}]_{radiation}*[t_{1/2}]_{excretion}}

\frac{1}{t_{1/2}}_{effective}} = \frac{[t_{1/2}]_{radiation}+[t_{1/2}]_{excretion}}{[t_{1/2}]_{radiation}*[t_{1/2}]_{excretion}}

\frac{1}{t_{1/2}}_{effective}} = \frac{9+6}{9*6}

\frac{1}{t_{1/2}_{effective}}}=\frac{15}{54}

t_{1/2}_{effective}} = \frac{54}{15}

= 3.6 days

5 0
4 years ago
Read 2 more answers
A weather balloon is inflated to a volume of 26.8 LL at a pressure of 744 mmHgmmHg and a temperature of 31.2 ∘C∘C. The balloon r
elena-s [515]

Answer:

43.96 L

Explanation:

We are given that

V_1=26.8 L

P_1=744mm Hg

T_1=31.2^{\circ} C=31.2+273=304.2K

P_2=385mmHg

T_2=-14.8^{\circ}=273-14.8=258.2K

We know that

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

V_2=\frac{P_1V_1T_2}{P_2T_1}

Substitute the values

V_2=\frac{744\times 26.8\times 258.2}{385\times 304.2}

V_2=43.96 L

Hence, the volume of balloon at -14.8 degree Celsius=43.96 L

5 0
3 years ago
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