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Lemur [1.5K]
3 years ago
13

Solve for w 1 − 0.5 = w

Mathematics
1 answer:
enot [183]3 years ago
7 0

Answer:

0.5

Step-by-step explanation:

1 - 0.5 = w

w = 1 - 0.5

w = 1.0 - 0.5

w = 0.5

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Last year, Deshaun had $20,000 to invest. He invested some of it in an account that paid 9% simple interest per year, and he inv
dezoksy [38]

Answer:

the amount Deshaun invested in an account that paid 9% interest = $9,000

the amount Deshaun invested in an account that paid 5% interest = $11,000

Step-by-step explanation:

Let x = the amount Deshaun invested in an account that paid 9% interest

Let y = the amount Deshaun invested in an account that paid 5% interest.

Thus;

x + y = 20,000 - - - - (eq 1)

Now, After one year, he received a total of $1440 in interest. Thus;

0.09x + 0.05y = 1440

Multiply each term by 100 to give;

9x + 5y = 144000 ---- (eq 2)

Making x the subject in equation 1,we have;

x = 20,000 - y

Putting 20,000 - y for x in eq 2,we have;

9(20,000 - y) + 5y = 1440

180000 - 9y + 5y = 144000

180000 - 4y = 144000

180000 - 144000 = 4y

36000 = 4y

Divide both sides by 4 to give;

y = 36000/4

y = $9,000

x = 20,000 - 9000

x = $11,000

7 0
3 years ago
Jamal drew a picture.
inessss [21]

area of rectangle = l×b

So, area of drawing = l×b = 8cm×4cm = 32cm²

7 0
3 years ago
Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.
Hitman42 [59]
\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
\\\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\

\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
\\\\\\
sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}

\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
\\\\\\
\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
-------------------------------\\\\
tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
\\\\\\
\textit{and now, let's rationalize the denominator}
\\\\\\
\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}

7 0
3 years ago
Simplify: (7+2a)·3–20 =
Black_prince [1.1K]
<h2>Greetings!</h2>

Answer:

6a + 1

Step-by-step explanation:

First, you need to multiply everything in the brackets by 3L

(7 + 2a) x 3 =

7 * 3 = 21

2a *  3 = 6a

21 + 6a

Now you can subtract the 20 from this:

6a + 21 - 20

Simplified down:

6a + 1


<h2>Hope this helps!</h2>
6 0
3 years ago
A. - 8/5<br><br>B. 5/8<br><br>C. - 5/8 <br><br>D. 8/5​
IrinaK [193]

Answer:

5/8

Step-by-step explanation:

To find the slope, use the formula

m = (y2-y1)/(x2-x1)

   = (2 - -3)/(6 - -2)

   = (2+3)/(6+2)

   = 5/8

5 0
3 years ago
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