Answer:20/47 meter per second
Explanation:
Mass of arrow(ma)=0.25kg
Velocity of arrow(va)=12m/s
Mass of target(mt)=6.8kg
Velocity of target(vt)=0 since target is at rest
Conservation of linear momentum says that :
maxva+mtxvt=(ma+mt)V
V=(maxva+mtxvt)/(ma+mt)
V=(0.25x12+6.8x0)/(0.25+6.8)
V=3/(7.05)
V=20/47 meter per second
Answer: They travel away from the focus of the earthquake in all directions.
Explanation:
The vibrations produced by Earthquake are called seismic waves. seismic waves travel from the point where fault occurs. The maximum intensity is about the focus of the fault. These waves travel away from the focus in all directions.
Seismic waves are both transverse (S waves) and longitudinal (P waves). The P and S waves can travel through the Earth where as the surface waves travel above or near the Earth's surface.
Answer:
B) 1/5 ba^2 T^5
Explanation:
The dissipated energy is given by the work done over the object by the force F=-bv. The work is given by the following formula:
![dW=Fdx](https://tex.z-dn.net/?f=dW%3DFdx)
you derivative the function f(x) and replace v by the derivative dx/dt you obtain:
![v=\frac{dx}{dt}=at^2\\\\dx=at^2dt\\\\W=\int_0^{T} Fdx=-\int_0^Tvbdx=-\int_0^Tb(at^2)(at^2dt)\\\\W=-ba^2\frac{T^5}{5}=-\frac{1}{5}ba^2T^5](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bdx%7D%7Bdt%7D%3Dat%5E2%5C%5C%5C%5Cdx%3Dat%5E2dt%5C%5C%5C%5CW%3D%5Cint_0%5E%7BT%7D%20Fdx%3D-%5Cint_0%5ETvbdx%3D-%5Cint_0%5ETb%28at%5E2%29%28at%5E2dt%29%5C%5C%5C%5CW%3D-ba%5E2%5Cfrac%7BT%5E5%7D%7B5%7D%3D-%5Cfrac%7B1%7D%7B5%7Dba%5E2T%5E5)
hence, the dissipated energy is 1/5 ba^2 T^5
Answer:
The base unit for time is the second (the other SI units are: metre for length, kilogram for mass, ampere for electric current, kelvin for temperature, candela for luminous intensity, and mole for the amount of substance). The second can be abbreviated as s or sec.
Explanation: