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ss7ja [257]
3 years ago
9

A dog accelerates at 1.50 m/s2 to reach a velocity of 13.5 m/s while covering a distance of 49.3 m. What was his initial velocit

y?
Physics
1 answer:
vovangra [49]3 years ago
7 0

Let <em>v</em> be the dog's initial velocity. Then

(13.5 m/s)^2 - <em>v</em> ^2 = 2 (1.50 m/s^2) (49.3 m)

==>   <em>v</em> ^2 = (13.5 m/s)^2 - 2 (1.50 m/s^2) (49.3 m)

==>   <em>v</em> = √((13.5 m/s)^2 - 2 (1.50 m/s^2) (49.3 m))

==>   <em>v</em> ≈ 5.86 m/s

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Based on Hooke's law, the spring constant of the the body's muscle mechanism is the ratio of force to extension, the effective mass is m/3 and the potential energy that can be stored is ke^2 / 2.

<h3>What is the spring constant?</h3>

The spring constant or stiffness constant of an elastic spring is constant which describes the extent a bit forceapplied to an elastic spring will extend it.

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