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maksim [4K]
3 years ago
15

Which value is equivalent to (7x5x2/7x3)^2 x (5^0/2^-3)^3 x2^-9?

Mathematics
1 answer:
koban [17]3 years ago
7 0

Answer:

100/9

Step-by-step explanation:

(7*5*2/7*3)² * (5^0/2^-3)³ * 2^-9

Solution:

We know that any number with power 0 = 1

(7*5*2/7*3)² * (1/2^-3)³ * 2^-9

Now cancel out 2 by 2

= (7*5*2/7*3)² * (1/1^-3)³ * 1^-9

=(70/21)² * (1)³/(1^-3)³ * 1^-9

=(10/3)^2 * 1/1^-1 * 1/1^9

=100/9 *1 *1

=100/9....

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Find the average rate of change of the function from <img src="https://tex.z-dn.net/?f=x_%7B1%7D" id="TexFormula1" title="x_{1}"
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Hi there!

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