Log 3 is the correct answer
Given :
a-b = c-d ...1)
b = d-1 ...2)
c = 6
To Prove :
a = 5
Solution :
Adding equation 1 and 2, we get :
(a-b) + (b) = (c-d) + (d-1)
a = c -1 ...3)
Putting given value of c = 6 in above equation, we get :
a = 6 - 1
a = 5
Hence, proved.
Answer:
A) To plot equations in point-slope form, pick one and let x = 0, then solve for y (or -4). That gives you point 1 (0,-4). Then let y = 0 and solve for x (or 2/3). That gives you a second point (2/3,0). Plot the two points and draw the line. Repeat for the second equation (points are (0,-3) and (3/5,0)). Where the lines cross is the solution for both equations.
B) point (1,2) fits both equations.
Step-by-step explanation:
Or solve by brute force...
The solution is where the same X,Y point fits both equations, or Y1 = Y2 and X1 = X2. So the equations in point-slope form (already in point-slope form) equal to each other, solve for X and plug that back into either of the equations to find Y.
6X - 4 = 5X -3
X = 1 so
y = 6X - 4
Y = 6 - 4
Y = 2
The French had many alliances with the Indians and the British had more troops. The French has to deal with untrained troops.
Hope this helps :)
