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jenyasd209 [6]
3 years ago
8

2. Find (w2 + 1)(w3 - W+1).

Mathematics
1 answer:
12345 [234]3 years ago
4 0

Answer:

w^{5} + w^{2} - w + 1

Step-by-step explanation:

We have to find the simplified expression of (w^{2} + 1) (w^{3} - w + 1).

Now, we have to multiply each term using the distributive property of multiplication.

So, (w^{2} + 1) (w^{3} - w + 1)

= w^{2} \times (w^{3} - w + 1) + 1 \times (w^{3} - w + 1)

= (w^{5} - w^{3} + w^{2} ) + (w^{3} - w + 1)

= w^{5} + w^{2} - w + 1 (Answer)

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If it’s greater than or equal to a negative will it’s second option switch to a positive?
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Vilka [71]
Primary equation: A(x)= (5y)(3X)
Secondary equation: 5y+3X=1000
y=200-(3X)/5
A(x)=3X(1000-3X)
A(x)=3000X-9X²

Now, find the derivative of A(x) to find the max... here's the work for that, or you could guess and check.

A'(x)=3000-18X

Set derivative equal to 0

0=3000-18X
166.6666666=X

Now test the intervals

(0,166.6666) (166.66666, 1000)
1st derivative is + 1st derivative is -

Plug the X value back into the secondary equation
5y+3(166.666666)=1000
5Y=500
Y=5

Answer:
X= 166.6666666666
Y=5

Please note, this is entry level calculus, and your teacher may expect you to use a different, longer route such as guess and check.
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