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omeli [17]
3 years ago
13

what’s the velocity of a bus travelling through a town with a mass of 5040 kg and kinetic energy of 493,900 j ?

Physics
1 answer:
Verdich [7]3 years ago
5 0

Answer:

The velocity of the bus is 14 m/s

Explanation:

Kinetic energy is directly proportional to the mass of the object and to

the square of its velocity

→ K.E = \frac{1}{2}mv², where K.E is the kinetic energy, m is the

mass, and v is the velocity

The unit of the kinetic energy is joule (j)

We need to find the velocity of a bus travelling through a town with a

mass of 5040 kg and kinetic energy of 493,900 j

→ K.E = 493900 j , m = 5040 kg

Substitute these values in the equation above

→ 493900 = \frac{1}{2}(5040)v²

Multiply both sides by 2

→ 987800 = (5040)v²

Divide both sides by 5040

→ 196.00 = v²

Take √ for both sides

→ v = 14 m/s

<em>The velocity of the bus is 14 m/s</em>

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Statements that are true as regards exposure control plan and its updating are;

<em>Updates must have the  reflection of changes in tasks as well in procedures.</em>

<em>Updates must reflect changes in positions that affect occupational exposure.</em>

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3 0
2 years ago
A bat moving at 3.7 m/s is chasing a ying insect. The bat emits a 36 kHz chirp and receives back an echo at 36.79 kHz. At what s
3241004551 [841]

Answer:

The speed the bat is gaining on its prey is 0.03m/s

Explanation:

Given;

speed of the bat, v₀ = 3.7 m/s

frequency of the bat, F₀ = 36 kHz

frequency of the source, Fs = 36.79

This is relative motion between a source of the sound and the observer.  The phenomenon is known as Doppler effect.

Apply the following equation to determine the speed of the insect which is the source;

F_0 = F_s[\frac{v+v_0}{v-v_s} ]\\\\\frac{F_0}{F_s} = [\frac{v+v_0}{v-v_s} ]\\\\\frac{36.79}{36} = \frac{340+3.7}{340-v_s}\\\\1.0219 = \frac{343.7}{340-v_s}\\\\  340-v_s = \frac{343.7}{1.0219}\\\\340-v_s = 336.33\\\\v_s = 340-336.33\\\\v_s = 3.67 \ m/s

The speed the bat is gaining on its prey = 3.7m/s - 3.67m/s = 0.03 m/s

Therefore, the speed the bat is gaining on its prey is 0.03m/s

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