what’s the velocity of a bus travelling through a town with a mass of 5040 kg and kinetic energy of 493,900 j ?
1 answer:
Answer:
The velocity of the bus is 14 m/s
Explanation:
Kinetic energy is directly proportional to the mass of the object and to
the square of its velocity
→ K.E = mv², where K.E is the kinetic energy, m is the
mass, and v is the velocity
The unit of the kinetic energy is joule (j)
We need to find the velocity of a bus travelling through a town with a
mass of 5040 kg and kinetic energy of 493,900 j
→ K.E = 493900 j , m = 5040 kg
Substitute these values in the equation above
→ 493900 = (5040)v²
Multiply both sides by 2
→ 987800 = (5040)v²
Divide both sides by 5040
→ 196.00 = v²
Take √ for both sides
→ v = 14 m/s
<em>The velocity of the bus is 14 m/s</em>
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Answer:
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(b) The distance-time graph for an object with non-uniform speed is giving by a curved line sloped graph with varying gradient as shown in the attached diagram
(c) The velocity-time graph for a car with uniform motion is giving by a horizontal line graph at the speed of constant motion with a zero gradient as shown in the attached diagram
(d) The velocity-time graph for a car moving with uniform acceleration is giving by a straight line sloped graph with a constant positive or negative gradient as shown in the attached diagram
(e) The velocity-time graph for a car moving with non-uniform acceleration is giving by a curved line sloped graph with varying gradient as shown in the attached diagram
(f) According to Newton's first law of motion, an object at rest will remain at rest with no motion unless acted by a force, an therefore, will have no motion with time
Explanation:
Answer:
h = 36.4 cm
Explanation:
given,
spring constant = 2.5 x 10⁴ N/m
compressed distance = 11.2 cm = 0.112 m
mass of the child = 44 kg
maximum height = ?
by energy of conservation
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h = 36.4 cm
Answer:
The object accelerates downward at 4 m/s² since the tension on the rope is less than weight of the object.
Explanation:
Given;
mass of the object, m = 2 kg
weigh of the object, W = 20 N
tension on the rope, T = 12 N
The acceleration of the object is calculated by applying Newton's second law of motion as follows;
T = F + W
T = ma + W
ma = T - W
(the negative sign indicates deceleration of the object)
The object accelerates downward at 4 m/s² since the tension on the rope is less than weight of the object.