Answer:
a) 55m/s
b)10m
c) 0.18 sec
Explanation:
a) In order to find the speed of the waves on the string can, we use the formula, i.e
v = sqrt (T/ μ)
where,
T = tension in the string
μ = linear density
μ linear density can be calculated by:
μ= m/L => 0.15/ 5 => 0.03 kg/m
v = sqrt (T/ μ)
v = sqrt ((90 / 0.03)
v= 55 m/s
therefore, the speed of the waves on the string is 55m/s
b) the wavelength of the standing wave produced can be determined by
λ = 2L /n ---->( n=1 because the string is vibrating to produce a standing wave at the fundamental frequency)
λ = 2 x 5 /1
λ = 10m
therefore, the wavelength of the standing wave produced is 10m
c) in order to find the period, lets first determine the frequency of standing waves.
f= v/ λ
f= 55 / 10
f= 5.5 Hz
next is to take the inverse of frequency as you know it is inversely proportional to period T
T= 1/f
T= 1/5.5
T= 0.18 s
thus, the period of the standing wave is 0.18 sec
