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Tju [1.3M]
3 years ago
12

You are walking in Paris alongside the Eiffel Tower and suddenly a croissant falls on your head and knocks you to the ground. If

you neglect air resistance, calculate how many seconds the croissant dropped before it knocked you over if the velocity is 76.4 m/s.
Physics
2 answers:
Alexxandr [17]3 years ago
6 0

Answer:

7,79 seconds

Explanation:

{\displaystyle {\overline {a}}={\frac {\Delta v}{t}}}

You need to use the acceleration formula. A is acceliration, \displaystyle \Delta \mathbf {v} is change in velocity and t is time.

You  need to multiply the formula with t and divide by a and you get

a*t=\displaystyle \Delta \mathbf {v}

t= \displaystyle \Delta \mathbf {v}/a

after that you just need to insert the numbers

change in velocity is 76.4 minus 0.

acceliration is gravitational acceleration which is 9.81.

After that you get

t=76.4/9.81

t= 7,787971458 s

egoroff_w [7]3 years ago
6 0

Answer:

seconds of freefall and calculate the velocity at impact in mi/hr. I VE = 10.78 m/s ... You are walking in Paris alongside the Eiffel Tower and suddenly a croissant smacks you on the head and knocks you to the ground. From your handy ... If you neglect air resistance, calculate how many seconds the croissant dropped before it.

Explanation:

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Answer:

\large \boxed{\text{C. 2.3 m/s}}

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m_{\text{A} } = \text{0.20 kg};\,v_{\text{Ai}} = \text{3.0 m/s}\\m_{\text{B} } = \text{0.40 kg};\,v_{\text{Bi}} = \text{2.0 m/s}\\

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This is a perfectly inelastic collision.  The two carts stick together after the collision and move with a common final velocity.

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Answer: y'=2Asin(kx)cos(wt)

Explanation:

Let y1=A sin (kx + wt) be the first wave

y2=A sin (kx - wt) be the second wave in the opposite direction (which we showed by putting a negative sign between the terms kx and wt)

Please do note that both wave have the same attributes (that's Amplitude, wave number and angular frequency) because they are formed on the same medium by the same source just that their directions are opposite.

By super imposing these 2 waves, we have a resulting singular wave representing both wave (law of superimposition) with a resulting value of vertical displacement y'.

Thus y' = y1 + y2.

Let us do the math.

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By factoring A out, we have that

y' = A [ sin (kx + wt) + sin (kx - wt)]

For simplicity let us use the substitution

Let (kx + wt) = a and (kx - wt) =b

Hence we have that

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By recalling that (kx + wt) = a and (kx - wt) =b

sin a + sin b = 2sin [(kx +wt +kx-wt) /2] * cos [(kx +wt - (kx-wt))/2]

Thus we have that

sin a + sin b = 2sin [(kx+wt+kx-wt)/2] * cos[(kx+wt-kx+wt)/2]

By collecting like terms in the bracket we have that

sin a + sin b = 2sin[2kx/2] * cos [2wt/2]

By dividing

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Recall that

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Finally,

y' = A [2sin(kx) cos(wt)] which is

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