All waves are known to undergo reflection or the bouncing off of an obstacle. Most people are very accustomed to the fact that light waves also undergo reflection. The reflection of light waves off of a mirrored surface results in the formation of an image.
Answer:
B
Explanation:
Newton’s Second Law of Motion
Newton’s Second Law of Motion states that ‘when an object is acted on by an outside force, the mass of the object equals the strength of the force times the resulting acceleration’.
This can be demonstrated dropping a rock or and tissue at the same time from a ladder. They fall at an equal rate—their acceleration is constant due to the force of gravity acting on them.
The rock's impact will be a much greater force when it hits the ground, because of its greater mass. If you drop the two objects into a dish of water, you can see how different the force of impact for each object was, based on the splash made in the water by each one.
Technically it’s asking what will happen to the skaters height it will rise to (the skaters highest point) if you change the initial height. Is this what you needed?
Answer:
a) P = 149140[w]; b) 1491400[J]; c) v = 63.06[m/s]
Explanation:
As the solution to the problem indicates, we must convert the power unit from horsepower to kilowatts.
P = 200 [hp]
![200[hp] * 745.7 [\frac{watt}{1 hp}]\\149140[watt]](https://tex.z-dn.net/?f=200%5Bhp%5D%20%2A%20745.7%20%5B%5Cfrac%7Bwatt%7D%7B1%20hp%7D%5D%5C%5C149140%5Bwatt%5D)
Now the power definition is known as the amount of work done in a given time
P = w / t
where:
w = work [J]
t = time [s]
We have the time, and the power therefore we can calculate the work done.
w = P * t
w = 149140 * 10 = 1491400 [J]
And finally, we can calculate the velocity using, the expression for kinetic energy
![E_{k}=w=0.5*m*v^{2}\\ where:\\v = velocity[m/s]\\m=mass=750[kg]\\w=work=1491400[J]\\](https://tex.z-dn.net/?f=E_%7Bk%7D%3Dw%3D0.5%2Am%2Av%5E%7B2%7D%5C%5C%20%20where%3A%5C%5Cv%20%3D%20velocity%5Bm%2Fs%5D%5C%5Cm%3Dmass%3D750%5Bkg%5D%5C%5Cw%3Dwork%3D1491400%5BJ%5D%5C%5C)
The key to solving this problem is to recognize that work equals kinetic energy
![v=\sqrt{\frac{w}{0.5*m}} \\v=\sqrt{\frac{1491400}{0.5*750}} \\v=63.06[m/s]](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%5Cfrac%7Bw%7D%7B0.5%2Am%7D%7D%20%20%5C%5Cv%3D%5Csqrt%7B%5Cfrac%7B1491400%7D%7B0.5%2A750%7D%7D%20%20%5C%5Cv%3D63.06%5Bm%2Fs%5D)
