Question

Q2) The position of an artillery, with a speed of projectile 650, which can fire in any direction above the horizontal plane and whose direction of fire can be adjusted necessarily and sufficiently fast, is (t) = 30 x 10m +20 x 10'my. Besides that, the position of a target is determined as Fr(t) =(-12 x 10 m + 100). Thus at which instant of time must the artillery be fired in order that the target is terminated as earlier as possible? (Ignore the friction, the air resistance and assume that there is no Coriolis force)

Answer 1

Answer:

The minimum time to reach the target is 2156s

Explanation:

Check attachment