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VARVARA [1.3K]
3 years ago
12

What is Biomass? What is Biofuel? Please help me science students

Physics
1 answer:
kramer3 years ago
7 0

Answer:

Biomass-Total of mass of organisms in a given area/volume

Biofuel-A fuel directly from living matter.

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Two concentric circular loops of wire lie on a tabletop, one inside the other. The inner wire has a diameter of 20.0 cm and carr
Harrizon [31]

Answer:

Explanation:

Magnetic field due to circular wire at the center = μ₀ I / 2 r

I is current and r is radius . μ₀ = 4π x 10⁻⁷.

field B₁ due to inner loop

B₁ = 4π x 10⁻⁷ x 12 / 2 x .20

= 376.8 x 10⁻⁷

Field due to outer loop

B₂ = 4π x 10⁻⁷ x I / 2 x .30

For equilibrium

B₁ = B₂

376.8 x 10⁻⁷ =  4π x 10⁻⁷ x I / 2 x .30

I = 18 A.

The direction should be opposite to that in the inner wire . It should be anti-clockwise.

4 0
3 years ago
The maximum range of projectle is R° if projected at angle of 45°. It'll be 300% of Range of projectile if projected at angle? a
geniusboy [140]

Answer:

The maximum range is 300% of the range of the projectile is projected at an angle of 9.74°.

None of the options are correct.

Explanation:

Normally, ignoring air resistance, for projectile motion, the range (horizontal distance travelled) of the motion is given as

R = (u² sin 2θ)/g

where

u = initial velocity of the projectile

θ = angle above the horizontal at which the projectile was launched

g = acceleration due to gravity = 9.8 m/s²

The range is maximum when θ = 45°

R when θ = 45° is

R = (u² sin 90°)/g = (u²/g)

We are then told that this maximum range is 300% of the value obtainable for the range at a particular angle

Maximum range = 3R

(u²/g) = 3(u² sin 2θ)/g

Sin 2θ = (1/3)

2θ = sin⁻¹ (1/3) = 19.47°

θ = (19.47°/2) = 9.74°

Hope this Helps!!!

4 0
3 years ago
Which material(s) listed below is an example of a persistent organic pollutant?
grigory [225]

Answer:

mercury

arsenic

ricin

ddt

Explanation:

pls mark me as brainliest

4 0
3 years ago
A solid cylinder of mass 20kg rolls without slipping down a 30° slope. Find the acceleration and the frictional force needed to
Alex_Xolod [135]

Answer:

a = 3.27 m/s²

F = 32.7 N

Explanation:

Draw a free body diagram.  There are three forces:

Weight force mg pulling straight down.

Normal force N pushing perpendicular to the slope.

Friction force F pushing parallel up the slope.

Sum of forces in the parallel direction:

∑F = ma

mg sin θ − F = ma

Sum of torques about the cylinder's axis:

∑τ = Iα

Fr = ½ mr²α

F = ½ mrα

Since the cylinder rolls without slipping, a = αr.  Substituting:

F = ½ ma

Two equations, two unknowns (a and F).  Substituting the second equation into the first:

mg sin θ − ½ ma = ma

Multiply both sides by 2/m:

2g sin θ − a = 2a

Solve for a:

2g sin θ = 3a

a = ⅔ g sin θ

a = ⅔ (9.8 m/s²) (sin 30°)

a = 3.27 m/s²

Solving for F:

F = ½ ma

F = ½ (20 kg) (3.27 m/s²)

F = 32.7 N

6 0
3 years ago
Starting with a new moon, name the phases the moon will pass through before the next new moon.
ipn [44]
Hope this helps! Please mark as brainliest!

8 0
3 years ago
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