Complete Question:
Football player A has a mass of 110 kg, and he is running down the field with a velocity of 2 m/s. Football player B has a mass of 120 kg and is stationary. What is the total momentum after the collision?
Answer:
Total momentum = 220 Kgm/s.
Explanation:
<u>Given the following data;</u>
For footballer A
Mass, M1 = 110kg
Velocity, V1 = 2m/s
For footballer B
Mass, M1 = 120kg
Velocity, V1 = 0m/s since he's stationary.
To find the total momentum;
Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.
Mathematically, momentum is given by the formula;
a. To find the momentum of A;
Momentum A = 220 Kgm/s.
b. To find the momentum of B;
Momentum B = 0 Kgm/s.
c. To find the total momentum of the two persons;
Substituting into the equation, we have;
<em>Total momentum = 220 Kgm/s. </em>
Can you provide the multiple choices ?
The acceleration of the bus is 1.11 meters per second square to the direction of motion
Explanation:
Acceleration is the rate of change of velocity
The formula of the acceleration is 
, where
is the initial velocity
is the final velocity- t is the time
A bus that goes from 10 km/h to a speed of 50 km/h in 10 seconds
→ = 10 km/h
→ = 50 km/h
→ t = 10 seconds
Change the unite of the time from seconds to hour
→ 1 hour = 60 × 60 = 3600 seconds
→ 10 seconds = 
hour
Substitute these values in the formula of the acceleration above
→ 
→ a = 14400 km/h²
To change the unit of acceleration to meter per second change the
kilometer to meter and the hour to seconds
→ 1 km = 1000 m
→ 1 hour = 3600 seconds
→ 
→ a = 1.11 m/sec².
The acceleration of the bus is 1.11 meters per second square to the direction of motion
Learn more:
You can learn more about the acceleration in brainly.com/question/6323625
#LearnwithBrainly
Not if both speeds are in the same units.
However, if the 254 is 'centimeters per time' and the 100 is 'inches per time',
then the speeds are equal.
