Question

Saki is ice-staking to the left with velocity of 5 m/s. A steady breeze starts blowing. Causing saki to accelerate leftward at a constant rate of 1.5 m/s2. After 6s , what is saki velocity

Answer 1

Answer:

Final velocity will be equal to 14 m/sec      

Explanation:

We have given initial velocity u = 5 m/sec

Constant acceleration is given $a=1.5m/sec^2$

Time t = 6 sec

We have to find the final velocity

From first equation of motion $v=u+at$, here v is final velocity, u is initial velocity , a is acceleration and t is time

So $v=5+1.5\times 6=14m/sec$

So equal final velocity will be equal to 14 m/sec