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expeople1 [14]
3 years ago
13

A rectangle is 24.6 m long and 8.65 m wide what is the area of this rectangle

Mathematics
2 answers:
MArishka [77]3 years ago
8 0
The area of this rectangle is 212.79 m
ella [17]3 years ago
5 0
5.46 x 8.65 = 21.279 m

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Eric's apartment is 1350 square feet, how many square meters of carpet will he need to order?​
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Please help me Simplify 3✔️2 - ✔️2
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\bf \stackrel{like~terms}{3\sqrt{2}-\sqrt{2}}\implies 2\sqrt{2}

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3 years ago
professor wrote the following inequalities for N number of students in his lecture. N <10, N>10, N<22, N>22. Turns o
m_a_m_a [10]

Answer:

There are N students in the class.

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N < 10

N > 10

N < 22

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We want only one of these four inequalities to be true.

Remember that if we have:

x > y

y is not a solution, because:

y > y is false.

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8 0
3 years ago
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
melamori03 [73]

Answer:

6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base b and height h is given by A=\frac{1}{2}bh. Therefore, the area of this right triangle is:

A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}

The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

The semi-perimeter, s, is:

s=\frac{5+5+4}{2}=\frac{14}{2}=7

Therefore, the area of the isosceles triangle is:

A=\sqrt{7(7-5)(7-5)(7-4)},\\A=\sqrt{7\cdot 2\cdot 2\cdot 3},\\A=\sqrt{84}, \\A=2\sqrt{21}\:\mathrm{cm^2}

Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

4 0
3 years ago
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