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gayaneshka [121]
3 years ago
15

1. The company has agreed on a 9- character password format, comprised of uppercase letters, lower case letters, and digits (0-9

). However, the rules specify that the first 3 characters have to be digits and the next 6 can be any upper case or lower case letter. How many possible passwords are there if: a. repetitions are allowed: b. repetitions are not allowed:
Mathematics
1 answer:
pochemuha3 years ago
5 0

Answer: a) 1977060966, b) 146581344.

Step-by-step explanation:

Since we have given that

There are 10 numbers,

There are 26 lower case letters,

There are 26 upper case letters,

Since the first 3 characters have to be digits and next 6 can be upper or lower.

So, a) repetitions are allowed:

10^3\times (26+26)^6\\\\=10^3\times 52^6\\\\=1977060966

b) repetitions are not allowed:

^{10}P_3\times ^{52}C_6\\\\=720\times 20358520\\\\=146581344

Hence, a) 1977060966, b) 146581344.

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What is the domain of the function f(x) = x + 2 ? a.    all real numbers greater         than -2 b.    all real numbers greater
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True or False : The distribution whose five- number summary is shown below has at least one outlier 4.2, 55.3, 73.4, 89.3, 132.2
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Read 2 more answers
See attached picture
yanalaym [24]

Answer:

\frac{f(x+h)-f(x)}{h}=2x + h

Step-by-step explanation:

Given

f(x)= x^2 + 2

Required

Determine: \frac{f(x+h)-f(x)}{h}

First, we calculate f(x + h)

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f(x+h) = (x+h)^2+2

f(x+h) = x^2+2xh+h^2+2

So, we have:

\frac{f(x+h)-f(x)}{h} = \frac{x^2 + 2xh + h^2 + 2 - x^2 - 2}{h}

\frac{f(x+h)-f(x)}{h}= \frac{x^2 - x^2+ 2xh + h^2 + 2  - 2}{h}

\frac{f(x+h)-f(x)}{h} = \frac{2xh + h^2}{h}

\frac{f(x+h)-f(x)}{h}=2x + h

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2 years ago
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