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ololo11 [35]
3 years ago
6

The wavelength of light is 310. nm; calculate the frequency.

Chemistry
2 answers:
Leto [7]3 years ago
5 0

Explanation:

It is given that wavelength of light is 310 nm or 310 \times 10^{-9} m. Relation between wavelength, speed of light and frequency is as follows.

                   \nu = \frac{c}{\lambda}

where,      \nu = frequency

                     c = speed of light = 3 \times 10^{8} m/s

                \lambda = wavelength

Hence, putting the given values into the above formula as follows.

             \nu = \frac{c}{\lambda}

            \nu = \frac{3 \times 10^{8} m/s}{310 \times 10^{-9} m}

                       = 9.67 \times 10^{14} per second

Thus, we can conclude that the frequency of given light is 9.67 \times 10^{14} per second.

kondor19780726 [428]3 years ago
4 0
Frequency = velocity of propagation / wavelength. 

<span>For light, we assume it is moving in a vacuum, so vp is 3e8 m/s. The wavelength of 310nm is 310e-9 meters. Then we plug the numbers in, and we get (3e8 m/s) / (310e-9 m) = 967.742e12 Hz because 1/s is the same as cycles/sec, which is a Hertz.</span>
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calculate the water potential of a solution of 0.15m sucrose. the solution is at standard temperature.
Mrac [35]

Answer:

The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.

Explanation:

Water potential = Pressure potential + solute potential

P_w=P_p+P_s

P_w=P_p+(-iCRT)

We have :

C = 0.15 M, T = 273.15 K

i = 1

The water potential of a solution of 0.15 m sucrose= P_w

P_p=0 bar (At standard temperature)

P_s=-iCRT=-\times 1\times 8.314\times 10^{-2}bar L/mol K\times 273.15 K=-3.406 bar

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The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.

7 0
2 years ago
Question 2: Heat (5 points)
Ronch [10]

Answer:

(i) specific heat

(ii) latent heat of vaporization

(iii) latent heat of fusion

Explanation:

i. Q = mcΔT; identify c.

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The amount of heat required to raise the temperature of substance of mass 1 kg by 1 degree C is known as the specific heat.  

ii. Q = mLvapor; identify Lvapor

Here, Q is the heat, m is the mass and L is the latent heat of vaporization.

The amount of heat required to convert the 1 kg liquid into 1 kg vapor at constant temperature.  

iii. Q = mLfusion; identify Lfusion

Here, Q is the heat, m is the mass and L is the latent heat of fusion.  

Here, Q is the heat, m is the mass and L is the latent heat of vaporization.

The amount of heat required to convert the 1 kg solid  into 1 kg liquid at constant temperature.  

8 0
3 years ago
Determine the number of moles in 4.21 x 10^23 molecules of CaCI2?????
Alla [95]

Explanation:

Given parameters:

Number of molecules = 4.21 x 10²³ molecules

Unknown parameters:

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Solution:

A mole can be defined as the amount of a substance that contains the avogadro's number of particles i.e 6.02 x 10²³

  To find the number of moles:

          Number of moles = \frac{number of molecules }{[tex]6.02 x 10^{23}}[/tex]

  Number of moles =  \frac{4.21 x 10[tex]^{23} }{6.02 x 10^{23}}[/tex]

Number of moles of CaCl₂ = 0.699moles

Learn more;

mole calculation brainly.com/question/13064292

#learnwithBrainly

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