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Yuri [45]
4 years ago
15

Which statement correctly describes the relationship between reactant and yield? The actual yield is calculated from the amount

of the excess reactant present. The actual yield is calculated from the amount of the limiting reactant present. The theoretical yield is calculated from the amount of the excess reactant present. The theoretical yield is calculated from the amount of the limiting reactant present.
Chemistry
2 answers:
melamori03 [73]4 years ago
8 0
The statement which correctly describe the relationship between the reactants and the yield is this: 'the theoretical yield is calculated from the amount of the limiting reactants present'. The theoretical yields is the ideal maximum amount of a product that can be produced during a chemical reaction while the limiting reactant is the reactant that determines the maximum amount of product that can be formed.
Vitek1552 [10]4 years ago
8 0

If you don't like reading to find the answer...

The theoretical yield is calculated from the amount of the limiting reactant present.

Option D or 4.

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4 years ago
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2. Fe(s) + O2(g) → Fe3O4(s) a. When 13.54 g of O2 is mixed with 12.21 g of Fe, which is the limiting reactant? b. What mass in g
julsineya [31]

The percent yield shows the extent to which the reactants are converetd into products . The limiting reactant is used up in the reaction.

<h3>What is a limiting reactant?</h3>

A limiting reactant is the reactant that is in the least amount in the system.  Now;

Number of moles of Fe =  12.21 g/56 g/mol = 0.22 moles

Number of moles of O2 = 13.54 g/32 g/mol = 0.42 moles

Balanced reaction equation;

3Fe(s) + 2 O2(g) = Fe3O4(s)

If 3 moles of Fe reacts with 2 mole of O2

0.22 moles of Fe reacts with  0.22 moles * 2 mole/3 moles = 0.15 moles

Hence, Fe is the limiting reactant

If 3 mole of Fe produces 1 mole of  Fe3O4(s)

 0.22 moles  of O2   produces   0.22 moles * 1 mole/3 moles of  Fe3O4(s) = 0.1073 moles

Mass of  Fe3O4(s) =0.1073 moles  * 232 g/mol =16.9 g

Number of moles of excess reactant = 0.42 moles - 0.15 moles = 0.27 moles

Mass of excess reactant = 0.27 moles * 32 g/mol = 8.64 g

percent yield = 15.88 g/16.9 g * 100/1

= 93.4%

Learn more about percent yiled: brainly.com/question/13463225

8 0
3 years ago
(Hurry ASAP!!!) There are 1.5 moles of methane (CH4) in a tank. It has a pressure of 4.4 atm at 173°C. Find the volume occupied
slamgirl [31]

Answer:

hope this help !

Explanation:

Use the given functions to set up and simplify 173 ° C .

1.5 =

CH4 = CH4

4.4 = CH4

173 ° C = CH4

8 0
3 years ago
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