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Yuri [45]
4 years ago
15

Which statement correctly describes the relationship between reactant and yield? The actual yield is calculated from the amount

of the excess reactant present. The actual yield is calculated from the amount of the limiting reactant present. The theoretical yield is calculated from the amount of the excess reactant present. The theoretical yield is calculated from the amount of the limiting reactant present.
Chemistry
2 answers:
melamori03 [73]4 years ago
8 0
The statement which correctly describe the relationship between the reactants and the yield is this: 'the theoretical yield is calculated from the amount of the limiting reactants present'. The theoretical yields is the ideal maximum amount of a product that can be produced during a chemical reaction while the limiting reactant is the reactant that determines the maximum amount of product that can be formed.
Vitek1552 [10]4 years ago
8 0

If you don't like reading to find the answer...

The theoretical yield is calculated from the amount of the limiting reactant present.

Option D or 4.

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Upon combustion, a compound containing only carbon and hydrogen produces 2.67 g<img src="https://tex.z-dn.net/?f=CO_%7B2%7D" id=
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Answer:

\boxed{\text{CH$_{2}$}}

Explanation:

1. Calculate the mass of each element

\text{Mass of C} = \text{2.67 g } \text{CO}_{2}\times \dfrac{\text{12.01 g C}}{\text{44.01 g }\text{CO}_{2}}= \text{0.7286 g C}\\\\\text{Mass of H} = \text{1.10 g }\text{H$_{2}$O}\times \dfrac{\text{2.016 g H}}{\text{18.02 g } \text{{H$_{2}$O}}} = \text{0.1231 g H}

2. Calculate the moles of each element

\text{Moles of C = 0.7286 g C}\times\dfrac{\text{1 mol C}}{\text{12.01 g C }} = \text{0.060 67 mol C}\\\\\text{Moles of H = 0.1231 g H} \times \dfrac{\text{1 mol H}}{\text{1.008 g H}} = \text{0.1221 mol H}

3. Calculate the molar ratios

Divide all moles by the smallest number of moles.

\text{C: } \dfrac{0.06067}{0.06067}= 1\\\\\text{H: } \dfrac{0.1221}{0.06067} = 2.015

4. Round the ratios to the nearest integer

C:H = 1:2

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