Answer:
a. 5.77L
b. 700mmHg
c. 395K
Explanation:
Using PV = nRT we can solve these problems where:
P is pressure of the gas in atm (1atm = 760mmHg)
V is volume in liters
n are moles of the gas
R is gas constant: 0.082atmL/molK
T is asbolute temperature in K
a. PV = nRT
V = nRT/P
P = 773mmHg*(1atm/760mmHg) = 1.017atm
T = 25°C+273 = 298K
V = 0.240mol*0.082atmL/molK*298K / 1.017atm
V = 5.77L
b. PV = nRT
P = nRT/V
P = 0.0947mol*0.082atmL/molK*309K/0.635L
P = 0.9216atm * (760mmHg/1atm) = 700mmHg
c. PV = nRT
PV/nR = T
P = 727mmHg * (1atm / 760mmHg) = 0.9566atm
0.9566atm*13.3L/0.393mol*0.082atmL/molK = T
T = 395K
