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Dominik [7]
2 years ago
9

Tyger is trying to eat less sugar in his diet.He reduces his sugar intake from 15 spoons a day to 9 1/2 spoons a day. What is th

e percentage reduction in his sugar intake.
Mathematics
1 answer:
seraphim [82]2 years ago
8 0

Answer:the percentage decrease is 36.67%

Step-by-step explanation:

Initial amount of sugar in his diet is 15 spoons in a day. Currently, the amount of sugar in his diet is 9 1/2 spoons in a day. Converting to decimal, it becomes 9.5 spoon in a day. The amount by which he reduced his sugar intake is 15 - 9.5 = 5.5 spoons.

Percentage decrease would be expressed as

Amount by which the intake decreased/ initial intake × 100

It becomes

5.5/15 × 100 = 36.67%

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Results from previous studies showed 79% of all high school seniors from a certain city plan to attend college after graduation.
alisha [4.7K]
<h2>Answer with explanation:</h2>

Let p be the population proportion.

Then, Null hypothesis : H_0 : p=0.79

Alternative hypothesis : H_a : p>0.79

Since the alternative hypothesis is right tailed , then the hypothesis test is a right tailed test.

Given :  A random sample of 200 high school seniors from this city reveals that 162 plan to attend college.

i.e. n = 200 > 30 , so we use z-test (otherwise we use t-test.)

\hat{p}=\dfrac{162}{200}=0.81

Test statistic for population proportion :

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}}

=\dfrac{0.81-0.79}{\sqrt{\dfrac{0.81(1-0.81)}{200}}}=0.720984093915\approx0.72

Thus, the z-value of the sample test-statistic = 0.72

P-value for right tailed test =P(z>0.72)=1-P(\leq0.72)

=1-0.7642375=0.2357625\approx0.2358

Since the p-value is greater than the significance level (0.05) , so we fail to reject the null hypothesis.

Hence, we conclude that we do not have sufficient evidence to support the claim that the percentage has increased from that of previous studies.

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3 years ago
6th grade math help me plzzzz
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Answer:

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Step-by-step explanation:

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Answer:

option 2

Step-by-step explanation:

consider the coordinates A (- 3, 4 ) and A' (- 1, \frac{4}{3} )

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