Answer:
Cable color codes are very important for example, If something is not wired properly, it can result in injuries, deaths, fires, and many other problems. This is why there are well-established wire color codes to ensure those working with an around this type of equipment can ensure everything is wired safely and effectively. If we used three phase cables without color code, this can lead too incorrect things that might be a hazard too get not fix and learning new color codes would be hard therefore we should stick too the same color codes for cables and it saves the hassle for needing too check every cable cord color then the original one signed too it.
Answer:
D. Less rain and snow.
Explanation:
A factor that can be a account for a drop in the water table is, less rain and snow. to topography, water tables is influenced by lot of factors, including the geology, weather, ground cover.
Answer:
The answer is explained below.
Explanation:
All the point on the disk has same angular acceleration. Here, the point P is at the midway between the center and the rim of the disk and the point Q is at rim of the disk.
So, the distance of the point Q from the axis is twicee the distance of the point P from the axis.
<em>Rp - R</em>
<em>Rq - 2R</em>
The linear acceleration is
α2 - Rα
So, the linear acceleration of Q is twice as great as the linear acceleration of P.
The speed of the particle when it is in the circular motion depends on the radius of the particle.
In this case, the speed of point Q is twice the speed of point P.
Answer:
a. 2.0secs
b. 20.4m
c. 4.0secs
d. 141.2m
e. 40m/s, ∅= -30°
Explanation:
The following Data are giving
Initial speed U=40m/s
angle of elevation,∅=30°
a. the expression for the time to attain the maximum height is expressed as
![t=\frac{usin\alpha }{g}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Busin%5Calpha%20%7D%7Bg%7D)
where g is the acceleration due to gravity, and the value is 9.81m/s if we substitute values we arrive at
![t=40sin30/9.81\\t=2.0secs](https://tex.z-dn.net/?f=t%3D40sin30%2F9.81%5C%5Ct%3D2.0secs)
b. the expression for the maximum height is expressed as
![H=\frac{u^{2}sin^{2}\alpha }{2g} \\H=\frac{40^{2}0.25 }{2*9.81} \\H=20.4m](https://tex.z-dn.net/?f=H%3D%5Cfrac%7Bu%5E%7B2%7Dsin%5E%7B2%7D%5Calpha%20%20%7D%7B2g%7D%20%5C%5CH%3D%5Cfrac%7B40%5E%7B2%7D0.25%20%7D%7B2%2A9.81%7D%20%5C%5CH%3D20.4m)
c. The time to hit the ground is the total time of flight which is twice the time to reach the maximum height ,
Hence T=2t
T=2*2.0
T=4.0secs
d. The range of the projectile is expressed as
![R=\frac{U^{2}sin2\alpha}{g}\\R=\frac{40^{2}sin60}{9.81}\\R=141.2m](https://tex.z-dn.net/?f=R%3D%5Cfrac%7BU%5E%7B2%7Dsin2%5Calpha%7D%7Bg%7D%5C%5CR%3D%5Cfrac%7B40%5E%7B2%7Dsin60%7D%7B9.81%7D%5C%5CR%3D141.2m)
e. The landing speed is the same as the initial projected speed but in opposite direction
Hence the landing speed is 40m/s at angle of -30°