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natka813 [3]
3 years ago
9

Are oil and water optically different

Physics
2 answers:
katovenus [111]3 years ago
6 0

Answer:

Yes

Explanation:

Trust me

Vanyuwa [196]3 years ago
3 0

Answer/Explanation:

Yes, water is normally clear, and oil is normally yellow, also water is heavier then oil so when mixed it will slowly separate.

Have an nice day and mark me brainliest! :)

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In which situation is the maximum possible work done? A. when the angle between the force and displacement is 0° B. when the ang
Flauer [41]

Answer:

C

Explanation:

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3 years ago
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If a force does a positive amount of work on an object, does the object's speed
Alexxandr [17]

The speed of the object increases

Explanation:

We can answer this question by applying the work-energy theorem, which states that the work done on an object is equal to the change in kinetic energy of the object. Mathematically:

W=K_f -K_i= \frac{1}{2}mv^2-\frac{1}{2}mu^2

where

W is the work done on the object

K_f, K_i are the final and initial kinetic energy of the object, respectively

m is the mass of the object

v is its final speed

u is its initial speed

In this case, the force does a positive amount of work on the object, so

W>0

This also implies that

K_f > K_i

And so

\frac{1}{2}mv^2 > \frac{1}{2}mu^2

And therefore

v>u

which means that the speed of the object increases.

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8 0
3 years ago
032. A 25.0 kg bicycle is traveling at a speed of 10.0 m/s.
dimulka [17.4K]
Answer:
A: 4
B: 7
C. 3
Source:
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(Don’t act put this I jus need to answer questions sorry)<\3
7 0
2 years ago
A motorcyclist accelerates from rest to 10 mi/hr. what is the change in velocity
gulaghasi [49]

The change in velocity is 10 mi/h (4.47 m/s)

Explanation:

The change in velocity of the motorcyclist is given by

\Delta v = v-u

where

v is the final velocity

u is the initial velocity

In this problem, we have

u = 0 (the motorbike starts from rest)

v = 10 mi/h

Therefore, the change in velocity is

\Delta v = 10 -0 = 10 mi/h

And keeping in mind that

1 mile = 1609 m

1 h = 3600 s

We can convert it into m/s:

\Delta v = 10 \frac{mi}{h} \cdot \frac{1609 m/mi}{3600 s/h}=4.47 m/s

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6 0
3 years ago
A mass of M-kg rests on a frictionless ramp inclined at 30°. A string with a linear mass density of μ=0.025" kg/m" is attached t
I am Lyosha [343]

Answer:

44.3 m/s

Explanation:

a) Draw a free body diagram of the mass M.  There are three forces:

Weight force mg pulling down,

Normal force N pushing perpendicular to the ramp,

and tension force T pulling parallel up the ramp.

Sum of forces in the parallel direction:

∑F = ma

T − Mg sin 30° = 0

T = Mg sin 30°

T = Mg / 2

Draw a free body diagram of the hanging mass m.  There are two forces:

Weight force mg pulling down,

and tension force T pulling up.

Sum of forces in the vertical direction:

∑F = ma

T − mg = 0

T = mg

Substitute:

mg = Mg / 2

m = M / 2

M = 2m

b) Velocity of a standing wave in a string is:

v = √(T / μ)

T = mg, and m = 5 kg, so T = (5 kg) (9.8 m/s²) = 49 N.  Therefore:

v = √(49 N / 0.025 kg/m)

v = 44.3 m/s

7 0
3 years ago
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