using the foil method multiply (5x+4)(5x-4) then add any like terms and write polynomial in standard form. Anybody have answers?
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2 answers:
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Given:
Dimensions of a tank are 50 cm by 32 cm by 20 cm
The tank is full of water and sand
Ratio of volume of water to the volume of sand is 5:1
To find:
Volume of water in the tank in liters
Solution:
Without loss of generality, let,
Length of tank = 50 cm
Breadth of tank = 32 cm
Height of tank = 20 cm
Then, we have,
Total Volume of the tank = Length * Breadth * Height
Total Volume = 50*32*20 cc
Total Volume = 32000 cc
It is given that,
Volume of water : Volume of sand = 5:1
(Volume of water)/(Volume of sand) = 5/1
Cross multiplying, we have,
Volume of sand = (Volume of water)/5
It is also given that the tank is full of water and sand. This implies that,
Volume of water + Volume of sand = Total Volume
Using the value, we obtained, we get,
Volume of water + (Volume of water)/5 = Total Volume
(6 * Volume of water)/5 = Total Volume
Plugging in the value of total volume, we get,
(6 * Volume of water)/5 = 32000 cc
Volume of water =
cc
Volume of water
26,666.6667 cc
We know that,
1 cc = 0.001 liters
26,666.6667 cc = (26666.6667 * 0.001) liters
26,666.6667 cc
26.667 liters
Thus, Volume of water in the tank is approximately 26.667 liters
Final Answer:
Volume of water in the tank (in liters) is approximately 26.667 liters
Answer:
a) 25% of the students exam scores fall below 55.6.
b) The minimum score for an A is 84.68.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 61 and a standard deviation of 8.
This means that
(a) What score do 25% of the students exam scores fall below?
Below the 25th percentile, which is X when Z has a p-value of 0.25, that is, X when Z = -0.675.
25% of the students exam scores fall below 55.6.
(b) Suppose the professor decides to grade on a curve. If the professor wants 0.15% of the students to get an A, what is the minimum score for an A?
This is the 100 - 0.15 = 99.85th percentile, which is X when Z has a p-value of 0.9985. So X when Z = 2.96.
The minimum score for an A is 84.68.