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3 years ago

Based on the image, which is not a wavelength?

Physics

1 answer:

ki77a [65]3 years ago

4 0

The distance that is not a wavelength in the image is C to E.

<h3>What is wavelength?</h3>

Wavelength is the distance between two successive crests or two successive trough or crest to trough.

It is also the distance over which the wave's shape repeats.

Based on the image, the following are wavelengths;

A to E, this is wavelength because it is between a crest and a trough.
B to F, this is wavelength because it is between two successive crest.
D to H, this is wavelength because it is between two successive trough.

Thus, the distance that is not a wavelength in the image is C to E.

Learn more about wavelength here: brainly.com/question/10728818

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Please help!

Trava [24]

Answer:

3 N to the right

Explanation:

There are two forces acting on the car:

- A force of 10 N towards the right

- A force of 7 N towards the left

Therefore, the net force is given by the difference between the two, since they are in opposite directions:

$F=10 N-7 N=3 N$

And the direction is to the right, since the force to the right has greater magnitude than the force to the left.

7 0

3 years ago

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What is one clam that supports global warming

krok68 [10]

The answer would be B

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4 years ago

A baseball pitcher delivers a fast ball. During the throw, the speed of the ball increases from 0 to 30.0 m/s over a time of 0.1

rosijanka [135]

B is the answer, i hope this helped

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2 years ago

A type of cuckoo clock keeps time by having a mass bouncing on a spring, usually something cute like a cherub in a chair. What f

Reil [10]

Answer:0.906 N/m

Explanation:

Given

time period $T=0.66 s$

mass $m=0.01 kg$

System can be considered as spring mass system

Time Period of spring mass system is given by

$T=2\pi \sqrt{\frac{m}{k}}$

squaring

$k=\frac{4\pi ^2m}{T^2}$

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4 0

3 years ago

Two infinite parallel surfaces carry uniform charge densities of 0.20 nC/m2 and -0.60 nC/m2. What is the magnitude of the electr

svlad2 [7]

Answer:

Electric field, E = 45.19 N/C

Explanation:

It is given that,

Surface charge density of first surface, $\sigma_1=0.2\ nC/m^2=0.2\times 10^{-9}\ C/m^2$

Surface charge density of second surface, $\sigma=-0.6\ nC/m^2=-0.6\times 10^{-9}\ C/m^2$

The electric field at a point between the two surfaces is given by :

$E=\dfrac{\sigma}{2\epsilon_o}$

$E=\dfrac{\sigma1-\sigma_2}{2\epsilon_o}$

$E=\dfrac{0.2\times 10^{-9}-(-0.6\times 10^{-9})}{2\times 8.85\times 10^{-12}}$

E = 45.19 N/C

So, the magnitude of the electric field at a point between the two surfaces is 45.19 N/C. Hence, this is the required solution.

6 0

3 years ago