In the serial dilution for the preparation of the dye, the total dilution factor is 1/20
<h3>What is dilution of solution?</h3>
Dilution is the process of preparing solutions of lesser concentration from a more concentrated solution.
In test tube 1:
Total volume = 60 mL
Dilution factor = 1:4
1 parts stock solution is required for every four parts diluent
Total parts = 5
volume of diluent = 4/5 × 60 mL = 48 mL
48 mL of diluent is added to 12 mL of stock solution to prepare the solution in test tube 1.
In test tube 2:
Total volume = 15 mL
Dilution factor = 1:5
1 parts stock solution is required for every five parts diluent
Total parts = 6
volume of diluent = 5/6 × 15 mL = 12.5 mL
12.5 mL of diluent is added to 2.5 mL of stock solution from tube 1 to prepare the solution in test tube 2.
Total dilution factor = 1/4 × 1/5 = 1/20
Learn more about dilution at: brainly.com/question/24881505
Answer:
<h2>The answer is 66 g</h2>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume of hexane = 100 m L
density = 0.66 g/mL
The mass is
mass = 0.66 × 100
We have the final answer as
<h3>66 g</h3>
Hope this helps you
Answer:
0.9483 grams of manganese dioxide should be added to excess HCl.
Explanation:
Pressure of the chlorine gas = P = 795 Torr = 1.046 atm (1 atm = 760 Torr)
Volume of the chlorine gas = V = 255 ml = 0.255 L
Temperature of the chlorine gas = T = 25°C= 298.15 K
Moles of chlorine gas = n
Using ideal gas equation:
PV = nRT
n = 0.01090 mol
According to reaction , 1 mole of chlorine gas is obtained from 1 mole of manganese dioxide.
Then 0.01090 moles of chlorine gas will be obtained from:
manganese dioxide
Mass of 0.01090 moles of manganese dioxide:
0.01090 mol × 87 g/mol = 0.9483 g
