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3 years ago

2Na + Cl2 → 2NaCl

Chemistry

1 answer:

antoniya [11.8K]3 years ago

4 0

<h3>Answer:</h3>

$\displaystyle 0.75 \ mol \ Cl_2$

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

Reading a Periodic Table
Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN] 2Na + Cl₂ → 2NaCl

[Given] 34.485 g Na

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Na = 1 mol Cl₂

Molar Mass of Na - 22.99 g/mol

<u>Step 3: Stoichiometry</u>

Set up: $\displaystyle 34.485 \ g \ Na(\frac{1 \ mol \ Na}{22.99 \ g \ Na})(\frac{1 \ mol \ Cl_2}{2 \ mol \ Na})$
Multiply/Divide: $\displaystyle 0.75 \ mol \ Cl_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 5 sig figs.</em>

Since our final answer has 2 sig figs, there is no need to round.

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The periodic table below shows which elements are metals, nonmetals, and metalloids. the element with the chemical symbol ______

aleksandr82 [10.1K]

H.
represents hydrogen element. under non metal classification.

for others, you'll find them under metal element classification.

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3 years ago

Given the table below, what is the chemical formula for a compound between Rb and the nitrate ion NO3-1?

lana [24]

Answer:

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3 years ago

What information is needed to determine the amount of moles in 1.6g of HCL?

alukav5142 [94]

Answer:

Molar mass and Mass

Explanation:

The relationship between mass and number of moles is given as;

Number of moles = Mass / Molar mass

Mass = 1.6 g

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Number of moles = 1.6 g / 36.5 g/mol

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8 0

3 years ago

State and explain the trend in electronegativity values across period 3 from sodium to chlorine

muminat

The trend in electronegativity values across period 3 from sodium to chlorine is that sodium with 11 protons is the least electromagnetic element and chlorine with 17 protons is the most electronegative element.

<h3>What is electronegativity?</h3>

It should be noted that electronegativity simply means a chemical property that describes the tendency of an atom to attract elements towards it.

In this case, the trend in electronegativity values across period 3 from sodium to chlorine is that sodium with 11 protons us the least electromagnetic element and chlorine with 17 protons is the most electronegative element.

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2 years ago

Please Balanced this Equation

Scilla [17]

Answer:

$\rm {Cr_2O_7}^{2-} + 6 \; Fe^{2+} + \underbrace{\rm 14\; H^{+}}_{\text{From}\atop \text{Acid}}\to 2\; Cr^{3+} + 6\; Fe^{3+} + 7\; H_2 O$ .

Explanation:

Consider the oxidation state on each of the element:

Left-hand side:

O: -2 (as in most compounds);
Cr: $\displaystyle \frac{1}{2}(\underbrace{-2}_{\text{ion}} - \underbrace{7\times (-2)}_{\text{Oxygen}}) = +6$ ;
Fe: +2 (from the charge of the ion);

Right-hand side:

Cr: +3;
Fe: +3.

Change in oxidation state:

Each Cr atom: decreases by 3 (reduction).
Each Fe atom: increases by 1 (oxidation).

Changes in oxidation states shall balance each other in redox reactions. Thus, for each Cr atom on the left-hand side, there need to be three Fe atoms.

Assume that the coefficient of the most complex species $\rm Cr_2O_7^{2-}$ is 1. There will be two Cr atoms and hence six Fe atoms on the left-hand side. Additionally, there are going to be seven O atoms.

Atoms are conserved in chemical reactions. As a result, the right-hand side of this equation will contain

two Cr atoms,
six Fe atoms, and
seven O atoms.

O atoms seldom appear among the products in acidic environments; they rapidly combine with $\rm H^{+}$ ions to produce water $\rm H_2O$ . Seven O atoms will make seven water molecules. That's fourteen H atoms and hence fourteen $\rm H^{+}$ ions on the product side of this equation. Hence the balanced equation. Double check to ensure that the charges on the ions also balance.

$\rm {Cr_2O_7}^{2-} + 6 \; Fe^{2+} + \underbrace{\rm 14\; H^{+}}_{\text{From}\atop \text{Acid}}\to 2\; Cr^{3+} + 6\; Fe^{3+} + 7\; H_2 O$ .

7 0

3 years ago