Answer:
Answer 'A'
Explanation:
In general, if the Σmolar volumes(g) reactants ≠ Σmolar volumes(g) products, a change in atmospheric pressure will shift the reaction equilibrium. If the pressure is increased, the rxn will shift toward the LOWER molar volume side of the rxn or if the pressure is decreased the rxn will shift toward the HIGHER molar volume side. For the reaction N₂O₄(g) ⇄ 2NO₂(g), Vm(N₂O₄(g)) < Vm(NO₂(g)) so, a decrease in atmospheric pressure would shift rxn toward the NO₂(g) side of the equation increasing the moles of NO₂(g). Also, note that if the Σmolar volumes(g) reactants = Σmolar volumes(g) products, no shift in equilibrium will occur regardless of changes in atmospheric pressure.
Answer:
Down is the recipe for momo..
Explanation:
recipe..
. Sieve the wheat flour carefully to remove lumps.
. Add water and knead the flour well to prepare a dough
. Remove the skin of the boiled potato ,cut into small pieces
. Heat the cooking oil in frying pan, and fry the pieces of onions cabbage green chili tomato pea etc.
. Prepare a mix veg stuffing by mixing potato other vegetables , green coriander and salt.
. Prepare a small balls of dough and roll it out of belna.
. Put 10 gm of mix vegetables stuff in the center of rolled dough and close it from all the sides to make a small ball.
. steam the momo for 10-15 minutes. After that it will be ready to serve.
. A sauce or pickle is usually eaten with momo.
Answer:
Element X has valency 2 while Y Valency 2, element Y has high tendency of gaining electrons for its stability thus the compound formed will be B
elements X is positively charged while Y will be negatively charged
Answer:
The tank with O₂ weighs more.
Explanation:
We can find the mass of gas using the ideal gas equation.

Considering the pressure (P), volume (V), temperature (T) and ideal gas constant (R) are the same, we can establish that:
m ∝ M
The mass is directly proportional to the molar mass. The molar mass of O₂ (32 g/mol) is higher than the molar mass of N₂ (28 g/mol). Therefore, the tank with O₂ weighs more.
2.2 x 10^-2
0.055 / 250 = 0.00022 - This would be 2.2 x 10^-4, but the question is asking for percent, not proportion, so multiply by 100% to get the percentage.
0.00022 * 100% = 0.022% = 2.2 * 10^-2