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Vanyuwa [196]
3 years ago
7

Cuantos gramos necesito para preparar una solución de 500 ml al 35% de NaCl

Chemistry
1 answer:
Iteru [2.4K]3 years ago
6 0
A patient who is prescribed a dose inhaler will find that it must be filled with a) medicine in powder form only. Works with lower (not upper) respiratory diseases only. Full of medicine used to give a fixed amount of medicine per oral inhalation. d) Medication in the form of a spray only.
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Select the correct identity of glacial acetic acid.
Lemur [1.5K]

Answer:

It is pure, anhydrous acetic acid is the correct answer.

Explanation:

  • Glacial acetic acid contains very less water that the reason it is called anhydrous.
  • Glacial acetic acid is a colorless, clear liquid and corrosive.
  • The glacial acetic acid in the diluted form used in vegetables and food preservation,flavoring in the slice, sausage, canned fruits and also it used to treat the bacteria and fungal infections.

6 0
3 years ago
What information is needed to calculate the average atomic mass of an element?(1 point)
g100num [7]

Answer:

Taking into account the definition of average atomic mass and isotopes of an element, the information that you need is the masses of its isotopes and their percent abundances.

Each chemical element is characterized by the number of protons in its nucleus, which is called the atomic number Z.

But in the nucleus of each element it is also possible to find neutrons, whose number can vary. The atomic mass (A) is obtained by adding the number of protons and neutrons in a given nucleus.

The same chemical element can be made up of different atoms, that is, their atomic numbers are the same, but the number of neutrons is different. These atoms are called isotopes of the element.

The atomic mass of an element is the weighted average mass of its natural isotopes. Therefore, the atomic mass of an element is not a whole number.

The weighted average means that not all isotopes have the same percentage.

In other words, the atomic masses of chemical elements are usually calculated as the weighted average of the masses of the different isotopes of each element, taking into account the relative abundance of each of them.

Explanation:

7 0
3 years ago
Describe, in detail, how to make 5.5 liters of a 2.5 molar HCl solution from a 10.5 molar HCl stock solution.
Misha Larkins [42]
The stock solution contains 10.5 moles of HCl per litre. A 5.5 litre solution of 2.5M HCl contains 5.5x2.5 = 13.75moles of HCl. Since every litre of stock solution provides 10.5M HCl, the amount of stock solution needed is 13.75/10.5 = 1.309L. Therefore you would dilute 1.309L of stock solution to 5.5L
5 0
3 years ago
In the reaction:
Ghella [55]

Answer:

The answer is D because NH4+and OH- it will be

N-1. N-1,

H-5

O-1 H-5

O-1

5 0
3 years ago
8.310x10^2 – 7.210x10^1<br><br>[?]x10^[?]​
alisha [4.7K]

Answer:

7.589\times 10^{2}

Explanation:

The expression can be solved mathematically as follows:

1) 8.310\times 10^{2}-7.210\times 10^{1} Given

2) 8.310\times 10^{1+1} - 7.210\times 10^{1} Definition of sum

3) (8.310\times 10^{1})\times 10^{1}-7.210\times 10^{1} a^{m+n} = a^{m}\cdot a^{n}/Associative property

4) (8.310\times 10^{1}-7.210)\times 10^{1} Distributive property

5) (83.100-7.210)\times 10^{1} Multiplication

6) 75.89\times 10^{1} Subtraction.

7) (7.589\times 10^{1})\times 10^{1} Multiplication/Associative property

8) 7.589\times (10^{1}\times 10^{1}) Associative property

9) 7.589\times 10^{2} a^{m+n} = a^{m}\cdot a^{n}/Result

7 0
3 years ago
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