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Vanyuwa [196]
3 years ago
7

Cuantos gramos necesito para preparar una solución de 500 ml al 35% de NaCl

Chemistry
1 answer:
Iteru [2.4K]3 years ago
6 0
A patient who is prescribed a dose inhaler will find that it must be filled with a) medicine in powder form only. Works with lower (not upper) respiratory diseases only. Full of medicine used to give a fixed amount of medicine per oral inhalation. d) Medication in the form of a spray only.
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What is not a typical step when performing scientific research
Gelneren [198K]

The six steps of the scientific are:

1. State the question

2. Conduct research

3. Create a hypothesis

4. Perform the experiment

5. Analyze the data

6. Conclusion

So D. would be the correct answer, even though communicating the results could possibly be a step if it's required.

8 0
3 years ago
What would cause the different liquids to have different density
Maksim231197 [3]
The masses of the liquids are different making them have different densities
3 0
3 years ago
Chlorine melts at 172 k what is chlorines melting point in C
Soloha48 [4]
<span><HTML><META HTTP-EQUIV="content-type" CONTENT="text/html;charset=utf-8"> <p class="answer-detail Fw-n" id="yui_3_17_2_3_1463589225479_1149"><SPAN class="ya-q-full-text" id="yui_3_17_2_3_1463589225479_1148" itemprop="text">K = 273.15 + C <BR><BR>K = 172 so substitute <BR><BR> 172 = 273.15 + C <BR><BR> C = 172 - 273.15 = -101.15</SPAN> </DIV></span>
7 0
3 years ago
Increasing the frequency _________________ the wavelength. Group of answer choices decreases increases does not change
Lesechka [4]

Answer:

heightens

Explanation:

3 0
3 years ago
The ksp of calcium carbonate, caco3, is 3.36 × 10-9 m2. calculate the solubility of this compound in g/l.
maw [93]
CaCO₃ partially dissociates in water as Ca²⁺ and CO₃²⁻. The balanced equation is,
                       CaCO₃(s) ⇄ Ca²⁺(aq) + CO₃²⁻(aq)
Initial                Y                   -                 -
Change           -X                  +X              +X
Equilibrium      Y-X                 X                X

Ksp for the CaCO₃(s) is 3.36 x 10⁻⁹ M²

                Ksp = [Ca²⁺(aq)][CO₃²⁻(aq)]
3.36 x 10⁻⁹ M² = X * X
3.36 x 10⁻⁹ M² = X²
                    X = 5.79 x 10⁻⁵ M

Hence the solubility of CaCO₃(s) = 5.79 x 10⁻⁵ M
                                                     = 5.79 x 10⁻⁵ mol/L

Molar mass of CaCO₃ = 100 g mol⁻¹

Hence the solubility of CaCO₃ = 5.79 x 10⁻⁵ mol/L x 100 g mol⁻¹
                                                 = 5.79 x 10⁻³ g/L

7 0
3 years ago
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