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user100 [1]
3 years ago
15

When is a roman numeral most likely needed in the name of an ionic compound? A)when more than one polyatomic ion appears

Chemistry
2 answers:
steposvetlana [31]3 years ago
8 0

D) When the cation is a transition metal.

For example, FeCl2 - iron (II) chloride vs FeCl3 - iron(III) chloride.

Mashutka [201]3 years ago
3 0

Answer is: D) when the cation is a transition metal.

The Roman numeral shows the charge and the oxidation state of the transition metal ion.

For example, cobalt can form two chlorides, with charge of 2+ (cobalt(II) chloride - CoCl₂) and with charge 3+ (cobalt(III) chloride - CoCl₃).

Transition metals are elements in the d-block of the periodic table.

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Predict whether the entropy change for this process is positive or negative and explain your answer. Then, predict whether the f
andrew11 [14]

The given question is incomplete. The complete question is:

Consider the spontaneous dissolution of NaCl in water: NaCl(s) → Na+(aq) + Cl −(aq) Predict whether the entropy change for this process is positive or negative and explain your answer. Then, predict whether the free energy change for the process is positive or negative and explain your answer.

Answer: The entropy change is positive. The free energy change for the process is negative and reaction is spontaneous.

Explanation:

Entropy is defined as the degree of randomness of a system. For a system in which randomness increses , the enetropy is said to increase and \Delta S is positive.

As in the given reaction : NaCl(s)\rightarrow Na^+(aq)+Cl^-(aq) , the solid is dissociating to give ions , randomness increases and thus entropy is positive.

Also the dissociation of a molecule requires energy , thus the enthalpy \Delta H is also positive as heat is absorbed by the system.

\Delta G=\Delta H-T\Delta S

\Delta G=(+ve)-T(+ve)

\Delta G=-ve when Temperature is high.

7 0
3 years ago
What is the reaction corresponding to the standard enthalpy of formation of K2SO3(s)?
nalin [4]

Answer:

  • 2K(s) + (1/8) S₈ (s) + (3/2) O₂(g)  →  K₂SO₃ (s)

Explanation:

The<em> standard enthalpy of formation </em>of a substance is the change in enthalpy that happens when one mole of the substance is formed from the elements in their standard states.

Thus, to calculate the standard state of formation of a compound you must:

  • 1. Identify the elements that form the compound
  • 2. Identify the standard form of each element
  • 3. Set the equation to form one mole of the compound, which may require to use fractional coefficients for some of the elements.

Applying that to our compound K₂SO₃

<u>1. Elements:</u>

  • potassium, K;
  • sulfur, S; and
  • oxygen, O.

<u />

<u>2. Standard forms of the elements:</u>

  • potassium: solid, K(s)
  • sulfur: solid, octatomic molecules, S₈ (s)
  • oxygen: diatomic gas, O₂(g)

<u>3. Reaction:</u>

  • K(s) + S₈ (s) + O₂(g)  →  K₂SO₃ (s)

Balance, keeping one mole of  K₂SO₃. You will need to use fractional coefficients for some elements:

  • 2K(s) + (1/8) S₈ (s) + (3/2) O₂(g)  →  K₂SO₃ (s) ← answer

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Answer:

2. d

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