a glass of ice at 0 degrees Celsius changes to a glass of water at 0 degrees Celsius what caused the ice to change to water

How does the sun's position in the sky affect rainbows?

IRINA_888 [86]

When the sun is low in the sky, light rays pass horizontally through more of the lower atmosphere to reach the earth's surface or an observer's eye. ... Because short-wavelength blue and green light are scattered more than red and yellow light, rainbows at times of sunrise and sunset often display the brightest reds.

3 0

3 years ago

A piston contains 0.39L of air at 1.0 atm. If the pressure on the piston is increased to 5.6 atm, what is the new volume?

bazaltina [42]

The new volume : 0.07 L

<h3>Further explanation</h3>

Boyle's Law

At a constant temperature, the gas volume is inversely proportional to the pressure applied

$\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}$

P₁=1 atm

V₁=0.39 L

P₂=5.6 atm

$\tt V_2=\dfrac{P_1.V_1}{P_2}\\\\V_2=\dfrac{1\times 0.39}{5.6}\\\\v_2=\boxed{\bold{0.07~L}}$

3 0

3 years ago

Any kind of help would be nice :)

alina1380 [7]

Answer:

1st page, number a-ENergy is added or absorbed

I cant see the answers on the 2nd page

Explanation:

8 0

3 years ago

Read 2 more answers

Technetium (Tc; Z = 43) is a synthetic element used as a radioactive tracer in medical studies. A Tc atom emits a beta particle

Sedaia [141]

Question in incomplete, complete question is:

Technetium (Tc; Z = 43) is a synthetic element used as a radioactive tracer in medical studies. A Tc atom emits a beta particle (electron) with a kinetic energy (Ek) of $4.71\times 10^{-15}J$ . What is the de Broglie wavelength of this electron (Ek = ½mv²)?

Answer:

$6.762\times 10^{-12} m$ is the de Broglie wavelength of this electron.

Explanation:

To calculate the wavelength of a particle, we use the equation given by De-Broglie's wavelength, which is:

$\lambda=\frac{h}{\sqrt{2mE_k}}$

where,

= De-Broglie's wavelength = ?

h = Planck's constant = $6.624\times 10^{-34}Js$

m = mass of beta particle = $9.1094\times 10^{-31} kg$

$E_k$ = kinetic energy of the particle = $4.71\times 10^{-15}J$

Putting values in above equation, we get:

$\lambda =\frac{6.624\times 10^{-34}Js}{\sqrt{2\times 9.1094\times 10^{-31} kg\times 4.71\times 10^{-15}J}}$

$\lambda = 6.762\times 10^{-12} m$

$6.762\times 10^{-12} m$ is the de Broglie wavelength of this electron.

3 0

3 years ago

The reaction that takes place when iron metal combines with aqueous hydrochloric acid.

Juli2301 [7.4K]

The reaction gives out a yellow showery sparks and produces a black solid. Iron reacts with dilute hydrocloric acid to give iron chloride and hydrogen gas.

2Fe+2Hcl3 = 2FeCl3+H2

8 0

3 years ago