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Ratling [72]
3 years ago
12

A pet owner dropped some new fish into a pond. Several species of fish lived in the pond, but within a few months, only members

of the new species survived. What best explains why this happened?
Chemistry
1 answer:
Daniel [21]3 years ago
8 0

Answer: the correct answer is : too many fish caused an imbalance in the ecosystem, so the food web was affected.

Explanation:

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5 0
4 years ago
What happens to iron oxide during decomposition
elena55 [62]

Answer:

it gets reduced from a +3 oxidation to a 0.

Explanation:

the decomposition of iron oxide to elemenTal can be represented by the following equation: iron oxide (Fe203), the oxidation state of iron is +3 while that of oxygen is -2. therefore, the above reaction is a redox (reduction oxidation reaction)

4 0
3 years ago
Assume that the partial pressure of sulfur dioxide, pso2, is equal to the partial pressure of dihydrogen sulfide, ph2s, and ther
Alex Ar [27]
<span>Kp = PH2O^2/(PH2O)^2 To calculate SO2 is to have a Kp for the reaction let x=PSO2=PH2S Kp= (28/760atm)^2/x^3 x=cube root(0.03684)/Kp=PSO2</span>
8 0
4 years ago
A wave at sea travel with a velocity of 25 m/s. If it has a wavelength of 10 m, what is it’s frequency?
stealth61 [152]

Answer:

2.5 Hz

Explanation:

Formula for the given question is:

Velocity= frequency X Wavelength.

v= f  X λ.

25 = 10 X f

f= 2.5 Hz

4 0
3 years ago
The total volume of seawater is 1.5 x 10²¹ L. Seawater contains approximately 3.5% sodium chloride by mass. At that high of a co
garri49 [273]

Answer:

There are 5.408\times 10^{22} grams contained in all the seawater in the world.

Explanation:

At first let is determinate the total mass of seawater (m_{sw}), measured in grams, in the world by definition of density and considering that mass is distributed uniformly:

m_{sw} = \rho_{sw}\cdot V_{sw}

Where:

\rho_{sw} - Density of seawater, measured in grams per liters.

V_{sw} - Volume of seawater, measured in liters.

If V_{sw} = 1.5\times 10^{21}\,L and \rho_{sw} = 1030\,\frac{g}{L}, then:

m_{sw}=\left(1030\,\frac{g}{L} \right)\cdot (1.5\times 10^{21}\,L)

m_{sw} = 1.545\times 10^{24}\,g

The total mass of sodium chloride is determined by the following ratio:

r = \frac{m_{NaCl}}{m_{sw}}

m_{NaCl} = r\cdot m_{sw}

Given that m_{sw} = 1.545\times 10^{24}\,g and r = 0.035, the total mass of sodium chloride in all the seawater in the world is:

m_{NaCl} = 0.035\cdot (1.545\times 10^{24}\,g)

m_{NaCl} = 5.408\times 10^{22}\,g

There are 5.408\times 10^{22} grams contained in all the seawater in the world.

8 0
4 years ago
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