C. Fixing a wineglass requires a large decrease in entropy.
Answer:
(a) 17,178 mg/m3
(b) 11,625 mg/m3
Explanation:
The concentration of CO in mg/m3 can be calculated as
For standard conditions (1 atm and 25°C), P/RT is 0.0409.
Concentration of 1.5% percent by volume of CO is equivalent to 1.5*10,000 ppm= 15,000 ppm CO.
The molecular weigth of CO is 28 g/mol.
(1) For 25°C and 1 atm conditions
(b) For 200°C and 1.1 atm,
Then the concentration in mg/m3 is
Answer and Explanation:
Dipole-Dipole interactions are <u>weaker than</u> hydrogen bonds.
Hydrogen bonds are a form of dipole-dipole interactions, being the strongest form of dipole-dipole interactions.
<em><u>#teamtrees #PAW (Plant And Water)</u></em>
Answer:
CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)
Explanation:
CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)
Methane + oxygen → carbon dioxide + Water.
The balanced equation above shows the combustion of methane, CH4 in oxygen, O2 to yield carbon dioxide, CO2 and steam, H2O.
The mole ratio of combustion are as follows:
1 mole of CH4 burns in 2 moles of oxygen to produce 1 mole of CO2 and 2 moles of H2O and a lot of heat.
Answer:5.309 × 10²⁴ atoms.
Explanation:
Given that
molar mass of NH3 = 17
g/mol
Mass of NH3 = 5g
Therefore, No of moles of NH3 = Mass/ molar mass
= 5g/ 17g/mol
= 0.294 moles.
I mole = 6.02 × 10²³ atoms
Therefore the number of hydrogen atoms in a 0.294 moles of ammonia gives us
0.294× 6.02 × 10²³ × 3 ( since there are 3 hydrogens in Ammonia )
= 5.309 × 10²⁴ atoms.
