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yKpoI14uk [10]
3 years ago
9

Quick question: are ionic compounds solid AND aqueous at room temperature. Or just solid at room temperature.

Chemistry
2 answers:
Daniel [21]3 years ago
6 0

Answer:  The strength of these connections are much stronger than the kinetic energy of the ions, and so they cannot break away from each other! Instead, the ions are held rigidly together in their organized crystal lattice structure, and that is why they are a solid under normal conditions

qwelly [4]3 years ago
5 0

Answer: All elemental ionic compounds are solid at room temperature, however there is a class of room temperature ionic liquids. [1] These are a result of poor coordination between the ions in solid form. Typically they involve ions

Explanation:

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If the question is referring to the 14th element on the periodic table (silicone) then it has 14 protons.
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Which of the following statements best provides evidence of the big bang theory?
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Which type of reaction always has an element and a compound as reactants?
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B. single-replacement

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When 35.0 mL of 0.400 M hydrobromic acid and 35.0 mL of 0.400 M ammonia are combined, the pH of the resulting solution will be :
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Answer:

B. Equal to 7.

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Hydrobromic acid is a strong acid that decreases pH and ammonia is a strong base that increases pH.

As the initial pH of water is 7,0 the addition of 35.0mL of 0.400M HBr will produce a pH less than 7,0. But, the same effect of decreasing pH is reverted for the addition of 35.0mL of 0.400M HNO3.

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I hope it helps!

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3 years ago
The atomic symbol Superscript 206 subscript 82 upper P b. represents lead-206 (Pb-206), an isotope that has 82 protons and 124 n
Serggg [28]

Answer:

\left \{ {{y=206} \atop {x=82}}Pb \right.

Explanation:

isotopes are various forms of same elements with different atomic number but different mass number.

Radioactivity is the emission of rays or particles from an atom to produce a new nuclei. There are various forms of radioactive emissions which are

  • Alpha particle emission  \left \{ {{y=4} \atop {x=2}}He \right.
  • Beta particle emission    \left \{ {{y=0} \atop {x=-1}}e \right.
  • gamma radiation             \left \{ {{y=0} \atop {x=0}}γ \right.

in the problem the product formed after radiation was Pb-206. isotopes of lead include Pb-204, Pb-206, Pb-207, Pb-208. they all have atomic number 82. which means the radiation cannot be ∝ or β since both radiations will alter the atomic number of the parent nucleus.

Only gamma radiation with \left \{ {{y=0} \atop {x=0}}γ \right. will produce a Pb-206 of atomic number 82 and mass number 206 , since gamma ray have 0 mass and has 0 atomic number.equation is shown below

\left \{ {{y=206} \atop {x=82}}Pb\right ⇒ \left \{ {{y=206} \atop {x=82}}Pb\right +  \left \{ {{y=0} \atop {x=0}}γ\right.

Thus the atomic symbol is \left \{ {{y=206} \atop {x=82}}Pb\right

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