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yKpoI14uk [10]
2 years ago
9

Quick question: are ionic compounds solid AND aqueous at room temperature. Or just solid at room temperature.

Chemistry
2 answers:
Daniel [21]2 years ago
6 0

Answer:  The strength of these connections are much stronger than the kinetic energy of the ions, and so they cannot break away from each other! Instead, the ions are held rigidly together in their organized crystal lattice structure, and that is why they are a solid under normal conditions

qwelly [4]2 years ago
5 0

Answer: All elemental ionic compounds are solid at room temperature, however there is a class of room temperature ionic liquids. [1] These are a result of poor coordination between the ions in solid form. Typically they involve ions

Explanation:

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The functional groups are written in the pictures attached. The first picture is aspirin. The functional groups are carboxylic group(O=COH), ester (O=COR), and aromatic group (benzene ring), where R is any hydrocarbon chain. The second picture is acetaminophen. The functional groups are amide group (O=CNHR), hydroxyl group (ROH) and aromatic group (benzene ring).

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3 years ago
- A beam of electrons has.....
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Answer:

(C) Both of these

Explanation:

A beam of electrons has both of these Wave properties and Particle properties.

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2 years ago
Lucy got a new car for her birthday so she went 12 km east and then 8 km South. What is her distance
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3 years ago
Some commercially available algaecides for swimming pools claim to contain 7% copper. Could the method used in this experiment t
AleksandrR [38]

Answer:

Explanation:

  1. 7% copper implies 7 w/v%(weight/volume %) of copper. This implies a 100 mL algaecide arrangement contains 7 grams of copper.  
  2. Henceforth we have a thought of the measure of copper that ought to be available in a given example of algaecide.  
  3. Indeed, even a 1 mL algaecide test is sufficient to discover the percentage of copper in it.  
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4 0
3 years ago
What mass of carbon dioxide is produced upon the complete combustion of 26.5 L of propane (the approximate contents of one 5-gal
svet-max [94.6K]

Answer:

mCO2= 49.6932 kgCO2

Explanation:

Hello! Let's solve this!

First we propose the balanced equation C3H8 + 5O2 ---> 3CO2 + 4H2O

We see that each mole of C3H8 (propane) we get 3 moles of CO2

From the propane volume we can obtain the grams of propane used.

molpropane = 26.5L * (1000mL / 1L) * (0.621g / 1mL) * (1mol / 44g) = 374.01mol propane

mCO2 = 374.01molC3H8 * (3molCO2 / 1molC3H8) * (44gCO2 / 1molCO2) = 49369.32g * (1kg / 1000g) = 49.6932 kgCO2

mCO2= 49.6932 kgCO2

6 0
3 years ago
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