Question

Devise a temperature scale, abbreviated g, for which the magnitude of the ideal gas constant is 1.00 j g–1 mol–1 .

Answer 1

The value of ideal gas constant (R) in Joule is 8.314 Joule $Kelvin^{-1}$$mol^{-1}$. Now the given expression is 1.00 J. g$g^{-1}.mole^{-1}$. Where the g represent the temperature. Thus the abbreviated g must have the value 8.314 to satisfy the original value. Thus the temperature scale will be 1 kelvin = 8.314 g. Now 1 kelvin  = -272.15°C or in terms of abbreviation of g we can write -272.15 °C = 8.314g, or, 1°C  = (-) $\frac{8.314}{272.15}=0.030$g. Thus the temperature scale of the g scale is 1 kelvin (K) = 8.314g and 1°C = 0.030 g.  

Answer 2

Answer:

Explanation:

Hello,

In this case, starting by the ideal gas constant as shown below:

$R=8.314\frac{J}{mol*K}$

In order to get the requested value, the following conversion should be applied:

$R=8.314\frac{J}{mol*K}*\frac{1K}{8.314G}=1\frac{J}{mol*G}$

Therefore, the obtained temperature scale implies that:

$1K=8.314G$

Best regards.